Fractions Recap

Write  $\frac{19}{3}$  as a mixed number

• 6

•  $5\frac{4}{3}$  

•  $6\frac{1}{3}$  

•  $7\frac{1}{3}$  

Which of these is the largest?

 $\frac{7}{4}$   $2\frac{1}{4}$   $\frac{12}{8}$   $3\frac{3}{4}$  

•  $\frac{7}{4}$  

•  $2\frac{1}{4}$  

•  $\frac{12}{8}$  

•  $3\frac{3}{4}$  

Write  $4\frac{1}{8}$  as an improper fraction

•  $\frac{33}{8}$  

•  $\frac{30}{8}$  

•  $\frac{31}{8}$  

•  $\frac{32}{8}$  

 $\frac{2}{5}+\frac{3}{7}=\frac{5}{12}$  

Is this correct?

• Yes.

• No, you cannot add denominators that aren't the same.

• No, 5 + 7 is not 12

• No, 2 + 3 is not 5

 $\frac{4}{5}+\frac{1}{2}$  

What is the first step in solving this problem? 

• Add the numerators

• Rewrite the fractions in the simplest form. 

• Make the denominators the same

• Add the denominators

 $\frac{8}{12}+\frac{3}{12}=$  

•  $\frac{24}{12}$  

•  $\frac{12}{24}$ 

•  $\frac{11}{12}$ 

•  $\frac{12}{12}$  

 $\frac{3}{2}+\frac{4}{5}=$  

•  $\frac{23}{10}$ 

•  $\frac{7}{7}$ 

•  $\frac{7}{10}$ 

•  $\frac{8}{15}$ 

 $\frac{3}{8}+\frac{4}{8}=$  

•  $\frac{12}{8}$  
  

•  $\frac{7}{8}$ 

•  $\frac{12}{64}$ 

•  $\frac{7}{12}$ 

 $\frac{2}{3}+\frac{3}{4}=$  

•  $\frac{5}{7}$ 

•  $\frac{6}{7}$ 

•  $\frac{17}{12}$ 

•  $\frac{7}{12}$ 

 $\frac{15}{16}-\frac{12}{16}=$  

•  $\frac{1}{3}$  

•  $\frac{4}{16}$  

•  $\frac{3}{16}$ 

•  $\frac{2}{16}$