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9.1-9.2 傾角和斜率 及 仰角和俯角

Authored by SUNG 宋穎欣

Mathematics

9th Grade

Used 7+ times

9.1-9.2  傾角和斜率 及 仰角和俯角
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8 questions

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1.

FILL IN THE BLANK QUESTION

1 min • 1 pt

先生沿一斜率為 1 : 16 的斜坡往上走。

求該斜坡的傾角,準確至三位有效數字。

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

圖中顯示一個斜面。
求該斜面的斜率。

220

440

 220440=12\frac{220}{440}=\frac{1}{2}  

 440220=2\frac{440}{220}=2  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

欣琳在一條傾角為 12 m 的直路向上步行。當欣琳步行的水平

距離為 80 m 時,求她步行的鉛垂距離 x

x80=sin 12°\frac{x}{80}=\sin\ 12\degree

x80=tan12°\frac{x}{80}=\tan12\degree

80x=cos 12°\frac{80}{x}=\cos\ 12\degree

80x=tan 12°\frac{80}{x}=\tan\ 12\degree

4.

FILL IN THE BLANK QUESTION

1 min • 1 pt

承上題,計算  x80=tan12°\frac{x}{80}=\tan12\degree  的值。( 答案準確至三位有效數字 )

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

圖中,一塊積木位於水平地面上的 B 點。一鉛垂杆 PQ 的高度是 4 m。若 B Q 的水平距離是 3.6 m,求由 B 測得 P 的仰角 θ\theta  。

 tanθ =43.6\tan\theta\ =\frac{4}{3.6}  

 tanθ =3.64\tan\theta\ =\frac{3.6}{4}  

 sinθ =43.6\sin\theta\ =\frac{4}{3.6}  

 sinθ =3.64\sin\theta\ =\frac{3.6}{4}  

6.

FILL IN THE BLANK QUESTION

1 min • 1 pt

承上題,計算  \tan\theta\ =\frac{4}{3.6} 的值。( 答案準確至最接近的度)

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

圖中,由水平地面 P 測得觀光塔塔頂 O 的仰角是 56°。若 P 與塔相距 27 m,求 OP

sin 56° =OP27\sin\ 56\degree\ =\frac{OP}{27}

cos 56° =OP27\cos\ 56\degree\ =\frac{OP}{27}

tan56° =27OP\tan56\degree\ =\frac{27}{OP}

cos 56° =27OP\cos\ 56\degree\ =\frac{27}{OP}

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