Grade 11, Chapter (11) - Trigonometry

Given that f(x) = sin 2x, then f(3π/ 2) =

• 0

• $-\frac{1}{2}$

• 1

• $\frac{1}{\sqrt{2}}$

Given that cos 60° = 1/ 2, then cos 120° =

• 1

• $-\frac{1}{2}$

• 0

• $\frac{1}{\sqrt{2}}$

sin (-180°) + cos (-270°) =

• 1

• $-\frac{1}{2}$

• 0

• $\frac{1}{\sqrt{2}}$

sin 45° sin 90° =

• 1

• $-\frac{1}{2}$

• 0

• $\frac{1}{\sqrt{2}}$

If cosec x = 13/ 5, 90° < x < 180°, then cos x =

• $-\frac{12}{13}$

• $-\frac{\sqrt{3}}{2}$

• $\frac{\sqrt{3}}{2}$

• $120\degree$

Let tan x = √3 . If tan x and cos x have opposite sign, then sin x =

• $-\frac{12}{13}$

• $-\frac{\sqrt{3}}{2}$

• $\frac{\sqrt{3}}{2}$

• $120\degree$

If cot x = √3, then tan (180° - x) =

• $-\frac{12}{13}$

• $-\frac{\sqrt{3}}{2}$

• $-\frac{1}{\sqrt{3}}$

• $120\degree$

If sin θ = √3/ 2, then the value of θ between 90° and 180° is

• $-\frac{12}{13}$

• $-\frac{\sqrt{3}}{2}$

• $-\frac{1}{\sqrt{3}}$

• $120\degree$

sin θ = 3/ 5 and θ is acute, then the value of sin 2θ =

• $\frac{24}{25}$

• $\frac{7}{25}$

• $0$

• $3$

sin θ = 3/ 5 and θ is acute, then the value of cos 2θ =

• $\frac{24}{25}$

• $\frac{7}{25}$

• $0$

• $3$