Grade 11, Chapter (9) - Areas of Similar Triangle

If two chords of circle AC, BD intersect at O. Then ∝(ΔAOB) : ∝(ΔCOD) =

• OA² : OD²

• OA² : CD²

• BA² : CD²

• OB² : OD²

The ratio of the sides of two equilateral triangles is 3 : 1, then the ratio of their area is

• 1 : 9

• 9 : 1

• 4 : 9

• 3 : 1

The area of two similar triangles are 16 sq-cm and 36 sq-cm respectively. Then the ratio of the altitudes is

• 9 : 1

• 4 : 3

• 2 : 3

• 3 : 1

The area of two similar triangles are 25 cm² and 36 cm² respectively. Then the ratio of the altitudes is

• 9 : 1

• 2 : 3

• 1 : 6

• 5 : 6

Two corresponding altitudes of two similar triangles are 8 cm and 10 cm. Then ∝(smaller Δ) : ∝(larger Δ) =

• 16 : 25

• 2 : 3

• 1 : 6

• 5 : 6

In the figure, AB=6, BE=3, CE=4√2, DE=4, then ∝(ΔABE) ∕ ∝(ΔCDE) =

• 1 : 9

• 9 : 16

• 2 : 3

• 3 : 1

In ΔABC, BD=3, DC=4 and ∝(ΔABD)=5, then ∝(ΔACD) is

• $\frac{20}{3}$

• 7

• $\frac{35}{3}$

• 4

In ΔPQR, RS=0.5QS, ∝(ΔPQS) : ∝(ΔPRS) =

• 16 : 25

• 2 : 3

• 1 : 6

• 5 : 2

If ΔABC ∼ ΔPQR, ∝(ΔABC) : ∝(ΔPQR) = 16 : 9, AB and PQ are corresponding sides and AB + PQ = 21 cm, then the length of AB in cm is

• 12

• 3

• 1

• 5

The sum and difference of areas of two similar triangles are 234 and 90. The ratio of corresponding sides is

• 16 : 25

• 3 : 2

• 1 : 6

• 5 : 6