Equations Review Perimeter and Area

The perimeter of a rectangle is 66 feet. The length is twice the width. Which equation would be used to find the length?

• w + 2w = 66

• 2w + 2w + w + w = 66

• 2w - w = 66

The perimeter of a rectangle is 66 feet. The length is twice the width. Write an equation to find the length and the width.

• width = 11 feet length = 22 feet

• width = 20 feet length = 10 feet

• width = 44 feet length = 22 feet

The perimeter of a rectangle is 48 inches. The length is represented by 2x - 6 and the width is 12 inches. Which equation would be used to find the length?

• 2x - 6 + 2x - 6 + 12 + 12 = 48

• 2x - 6 + 12 = 48

• 2(2x - 6) - 12 = 48

The perimeter of a rectangle is 48 inches. The length is represented by 2x - 6 and the width is 12 inches. Write an equation to find the length.

• length = 10 inches

• length = 16 inches

• length= 12 inches

• length = 14 inches

The area of a rectangle is 92 square inches. The length is represented by 2x + 3 and the wide is 4 inches. Which equation can be shown to find the length?

• 2x + 3 + 4 = 92

• 4(2x + 3) = 92

• 4 - 2x + 3 = 92

The area of a rectangle is 92 square inches. The length is represented by 2x + 3 and the wide is 4 inches. Write an equation to find the length.

• length = 14 inches

• length = 23 inches

• length = 26 inches

• length = 32 inches

The area of a rectangle is 81 square feet. The length is represented by x + 2 and the width is 3 feet. Write an equation to find the length.

• length = 21 inches

• length = 23 inches

• length = 25 inches

• length = 27 inches

The area of a rectangle is 81 square feet. The length is represented by x + 2 and the width is 3 feet. Which equation can be used to find the length?

• 3(x + 2) = 81

• 3 + 3 + x + 2 + x + 2 = 81

• 3 - x + 2 = 81

Solve the equation 3x - 9 = 12. ONLY TYPE THE NUMERIC VALUE IN THE BLANK.

Solve the equations 4(x +2) = 32. TYPE THE NUMERIC ANSWER ONLY.