Differential Equations Review

Differential Equations Review

11th Grade - University

20 Qs

quiz-placeholder

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Differential Equations Review

Differential Equations Review

Assessment

Quiz

Mathematics

11th Grade - University

Hard

Created by

Art Young

Used 22+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Which of the following differential equations match the graph above?

 

 dydx=y21\frac{\text{d}y}{\text{d}x}=y^2-1  

 dydx=x21\frac{\text{d}y}{\text{d}x}=x^2-1  

 dydx=y2+1\frac{\text{d}y}{\text{d}x}=y^2+1  

 dydx=x2+1\frac{\text{d}y}{\text{d}x}=x^2+1  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Suppose y=f(x) is a particular solution to the differential equation dy/dx=x–y such that f(0)=0. Use the slope field above to estimate the value of f(2).

-2

-1

0

1

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Match the following differential equation with the correct slope field: dy/dx=x–y^2.

Media Image
Media Image
Media Image
Media Image

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Shown above is a slope field for which of the following differential equations?

dydx=1+x\frac{dy}{dx}=1+x

dydx=x2\frac{dy}{dx}=x^2

dydx=x+y\frac{dy}{dx}=x+y

dydx=xy\frac{dy}{dx}=\frac{x}{y}

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which of the following is the solution to the differential equation dy/dx=(x^2)/y with initial condition y(3)=-2?

y=2e9+x33y=2e^{\frac{-9+x^3}{3}}

y=2e9+x33y=-2e^{\frac{-9+x^3}{3}}

y=2x33y=\sqrt{\frac{2x^3}{3}}

y=2x3314y=\sqrt{\frac{2x^3}{3}-14}

y=2x3314y=-\sqrt{\frac{2x^3}{3}-14}

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve the differential equation dy/dx=e^2x in terms of y given the condition that y(0)=0.

y=12e2x+12y=\frac{1}{2}e^{2x}+\frac{1}{2}

y=12e2x12y=\frac{1}{2}e^{2x}-\frac{1}{2}

y=12e2x+13y=\frac{1}{2}e^{2x}+\frac{1}{3}

y=12e2x13y=\frac{1}{2}e^{2x}-\frac{1}{3}

y=12ex12y=\frac{1}{2}e^x-\frac{1}{2}

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve the differential equation dy/dx=y/1+x^2 in terms of y given the condition that y(0)=1.

y=ln1+x2y=\ln\left|1+x^2\right|

y=2ln1+x2y=2\ln\left|1+x^2\right|

y=e2arctan(x)y=e^{2\arctan\left(x\right)}

y=earctan(x)y=e^{\arctan\left(x\right)}

y=earctan(2x)y=e^{\arctan\left(2x\right)}

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