B2T1L3: Apply the Distributive Property to Multiply

Split the Factor Greater than 10

17 x 5

___ + ____ x 5

• 10 + 5

• 10 + 7

• 17 + 10

• 17 + 5

Tags

CCSS.3.OA.B.5

What are the partial products (two equations) found using the Distributive Property ?

(10 + 7) x 5

(Choose TWO ANSWERS)

• 10 x 7

• 10 x 5

• 7 x 7

• 7 x 5

Tags

CCSS.3.OA.B.5

Find the Answer using the Partial Products

17 x 5 = (10 + 7) x 5

10 x 5 = ? + 7 x 5 =?

• 50 + 35 = 85

• 15 + 12 = 27

• 17 + 35 = 52

• 5 + 17 = 22

Tags

CCSS.3.OA.B.5

CCSS.3.OA.C.7

Split the Factor Greater than 10 and rewrite the Equation using the Distributive Property.

13 x 8 = ?

• (10 + 8) x 3

• (13 + 1)

• 13 x (9 + 1)

• (10 + 3) x 8

Tags

CCSS.3.OA.B.5

Check the TWO partial Products that would be used to find the answer using the Distributive Property ?

13 x 8 = (10 + 3) x 8

• 3 x 8 = 24

• 10 x 8 = 80

• 10 x 3 = 30

• 3 x 13 = 39

Tags

CCSS.3.OA.B.5

Using the Partial Products, what is the answer to this problem ?

13 x 8 = (10 + 3) x 8

• 80 + 24 = 104

• 10 + 8 = 18

• 3 + 8 = 11

• 13 + 8 = 21

Tags

CCSS.3.OA.B.5

CCSS.3.OA.C.7

Find the Partial Products using the Distributive Property :

14 x 4 = (10 + 4) x 4

• 1 x 4 = 4

• 10 x 4 = 40

• 4 x 4 = 16

• 10 x 1 = 10

Tags

CCSS.3.OA.B.5

Find the Answer using Partial Products:

14 x 4 = (10 + 4) x 4 = ?

• 20 + 4 = 24

• 40 + 16 = 56

• 10 + 4 = 14

• 3 + 1 = 4

Tags

CCSS.3.OA.B.5

CCSS.3.OA.C.7

Find the Partial Products using the Distributive Property :

6 x 15 = 6 x (10 + 5)=

• 6 x 15= 90

• 6 x 5 = 30

• 6 x 7 = 42

• 6 x 10 = 60

Tags

CCSS.3.OA.B.5

Find the Product using the Partial Products Listed Below:

6 x 15 = 6 x (10 + 5) =

• 60 + 30 = 90

• 16 + 11 = 27

• 6 + 15 = 21

• 50 + 6 = 56

Tags

CCSS.3.NBT.A.3

CCSS.3.OA.B.5