1 81 = 3 − 4 \frac{1}{81}=3^{-4} 8 1 1 = 3 − 4 , significa que:

log ⁡ 3 ( 1 81 ) = − 4 \log_3\left(\frac{1}{81}\right)=-4 lo g 3 ( 8 1 1 ) = − 4

log ⁡ 4 ( 1 81 ) = − 3 \log_4\left(\frac{1}{81}\right)=-3 lo g 4 ( 8 1 1 ) = − 3

log ⁡ 3 ( 1 81 ) = 4 \log_3\left(\frac{1}{81}\right)=4 lo g 3 ( 8 1 1 ) = 4

log ⁡ − 3 ( 81 ) = 4 \log_{-3}\left(81\right)=4 lo g − 3 ( 8 1 ) = 4

log ⁡ 15 225 = 2 \log_{15}225=2 lo g 1 5 2 2 5 = 2

225 = 15 \sqrt{225}=15 2 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 1 5

15 = 225 \sqrt{15}=225 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 2 2 5

2 = 225 \sqrt{2}=225 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 2 2 5

Logaritmos Quiz

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Si Log _x 256 = 4, entonces x es

-4

4

-4 y 4

8

256

Tags

CCSS.HSF.BF.B.5

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Log ₅ 625 = X

5

4

3

2

Tags

CCSS.HSF.BF.B.5

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Log ₂ 128 - Log ₂32 =

-4

-2

128 / 32

2

4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Log 4 + Log 6 - log 2 =

Log 8

Log (-8)

2 Log 24

Log 12

Log (-12)

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Log 10000

3

4

5

6

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

log₃₀1 =

0

1

30

-1

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\log_5125=3$ , significa que:

$5^3=125$

$3^5=125$

$\frac{125}{5}=25$

Tags

CCSS.HSF.BF.B.5

8.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\frac{1}{81}=3^{-4}$ , significa que:

$\log_3\left(\frac{1}{81}\right)=-4$

$\log_4\left(\frac{1}{81}\right)=-3$

$\log_3\left(\frac{1}{81}\right)=4$

$\log_{-3}\left(81\right)=4$

9.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\log_{16}2\$
Calcule

1/4

1/2

2

4

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\log_62\ +\ \log_63$
Calcular

1

6

2

3

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Logaritmos

Si Log x 256 = 4, entonces x es

Log 5 625 = X

Log 2 128 - Log 2 32 =

Log 4 + Log 6 - log 2 =

Log 10000

log30 1 =

log⁡5125=3\log_5125=3log5​125=3 , significa que:

181=3−4\frac{1}{81}=3^{-4}811​=3−4 , significa que:

log⁡162 \log_{16}2\ log16​2 Calcule

log⁡62 + log⁡63\log_62\ +\ \log_63log6​2 + log6​3 Calcular

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Si Log _x 256 = 4, entonces x es

Log ₅ 625 = X

Log ₂ 128 - Log ₂32 =

log₃₀1 =

$\log_5125=3$ , significa que:

$\frac{1}{81}=3^{-4}$ , significa que:

$\log_{16}2\$
Calcule

$\log_62\ +\ \log_63$
Calcular