Unit 2B: Midsegment and Side-Splitter Theorem Practice

All corresponding angles in similar figures are congruent.  

• True
• False

Tags

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.A.3

CCSS.HSG.SRT.B.5

Two objects that are the same shape but not the same size are _______.

• Congruent
• Vertical
• Similar
• Complementary 

Tags

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.A.3

Find the missing length.

• 4
• 10
• 8
• 12

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the missing length.

• 21
• 18
• 16
• 24

Tags

CCSS.7.G.A.1

Complete each proportion.
CB / DM  =  AC / ?

• BM
• MA
• BC
• AD

Tags

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.A.3

CCSS.HSG.SRT.B.5

If AB = 4, BC = 7, ED = 5, and EC = 13.75, determine whether BD is parallel to AE.

• Yes
• No

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.CO.C.9

CCSS.HSG.GPE.B.5

CCSS.HSG.SRT.B.4

Solve for x.

• 10

• 5

• 7

• 4

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

CCSS.HSG.SRT.B.5

Find the missing length.

• 35
• 28
• 42
• 13

Tags

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.A.3

CCSS.HSG.SRT.B.5

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.D.11

Which proportion would be correct in order to solve for x.  (Hint: remember the side splitter theorem states the sides of the triangles are proportional)

• x/10 = 15/30
• x/10 = 45/30
• x/10 = 15/45
• x/10 = 30/15

Tags

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.B.5

The Side Splitter Theorem states that If a line is parallel to one side of a triangle and intersects the other two sides, then  $\frac{AB}{BC\ }=\frac{AE}{?}$  What is the question mark?

• BE

• CD

• AD

• ED

Tags

CCSS.HSG.SRT.B.4