Standard Form to Slope Intercept Form

what is the first step to solve for slope intercept form on

-x + 4y = 11

• subtract 11 from both sides

• add x to both sides

• subtract x from both sides

• put in th y=

Tags

CCSS.8.F.A.3

CCSS.8.EE.B.6

which of the following is the best first step to solve for y = mx +b? equation is -2x - 4y = -12

• add 4y to both sides

• subtract 2x from both sides

• add 2x to both sides

• divide by -4

Tags

CCSS.HSA.CED.A.4

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

what is the last step to finish solving for y= mx+ b for the equation 3y = -5x + 10

• divide everything by - 3

• subtract 3y from both sides

• divide everything by 3

• add 3y from both sides

Tags

CCSS.HSA.CED.A.4

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Write in slope intercept form
5x - 3y = -9

• y = (5/3)x - 3
• y = (5/3)x + 9
• y = (5/3)x + 3
• y = (3/5)x + 3

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Write the equation in slope-intercept form:
-3y + 5x = 12

• y = -4 + 5x
• y = -4 + 5/3x
• y = 4 - 5/3x
• y = 12 + 5x

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Write in slope intercept form
5x - 3y = -9

• y = (5/3)x - 3
• y = (5/3)x + 9
• y = (5/3)x + 3
• y = (3/5)x + 3

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.CED.A.4

CCSS.HSS.ID.C.7

Write the equation in slope-intercept form:
-3y + 5x = 12

• y = -4 + 5x
• y = -4 + 5/3x
• y = 4 - 5/3x
• y = 12 + 5x

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Write in slope intercept form
5x - 3y = -9

• y = (5/3)x - 3
• y = (5/3)x + 9
• y = (5/3)x + 3
• y = (3/5)x + 3

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.CED.A.4

CCSS.HSA.REI.D.10

Write the equation in slope-intercept form:
-3y + 5x = 12

• y = -4 + 5x
• y = -4 + 5/3x
• y = 4 - 5/3x
• y = 12 + 5x

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Write the equation in slope-intercept form:
-3y + 5x = 12

• y = -4 + 5x
• y = -4 + 5/3x
• y = 4 - 5/3x
• y = 12 + 5x

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3