MIDTERM EXAM IN INTEGRAL CALCULUS [5pts each]

MIDTERM EXAM IN INTEGRAL CALCULUS [5pts each]

University

11 Qs

quiz-placeholder

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MIDTERM EXAM IN INTEGRAL CALCULUS [5pts each]

MIDTERM EXAM IN INTEGRAL CALCULUS [5pts each]

Assessment

Quiz

Mathematics

University

Hard

Created by

MARK JEROME DE LA PEÑA

Used 31+ times

FREE Resource

11 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Find the Antiderivative of

 13x35x\frac{1}{3}x^3-5x  

 112x45x2+c\frac{1}{12}x^4-5x^2+c  

 12x4+5x2+C12x^4+5x^2+C  

 112x35x2+c\frac{1}{12}x^3-5x^2+c  

 112x45x2+c\frac{1}{12}x^4-5x^2+c  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 (e(32x))dx\int\left(e^{\left(3-2x\right)}\right)dx  

 12e(32x)+c-\frac{1}{2}e^{\left(3-2x\right)}+c  

 2e(32x)+c-2e^{\left(3-2x\right)}+c  

 (32x)e(32x)+c-\left(3-2x\right)e^{\left(3-2x\right)}+c  

 e(32x)+c-e^{\left(3-2x\right)}+c  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 (x3e2x4)dx\int\left(x^3e^{2x^4}\right)dx  

 18e2x4+c\frac{1}{8}e^{2x^4}+c  

 3x2e2x4+c3x^2e^{2x^4}+c  

 18x3e2x4+C\frac{1}{8}x^3e^{2x^4}+C  

 14e2x4+c\frac{1}{4}e^{2x^4}+c  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 (3+e4x)e2x dx\int\frac{\left(3+e^{4x}\right)}{e^{2x}\ }dx  

 32e2x+12e2x+c-\frac{3}{2}e^{-2x}+\frac{1}{2}e^{2x}+c  

 3e2x+e2x+c3e^{-2x}+e^{2x}+c  

 6e2x+2e2x+c-6e^{-2x}+2e^{2x}+c  

 (3x+4e4x)2ex+c\frac{\left(3x+4e^{4x}\right)}{2e^x}+c  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

  e5x43e5xdx\int\frac{\ e^{5x}}{4-3e^{5x}}dx  

 115ln43e5x+c-\frac{1}{15}\ln\left|4-3e^{5x}\right|+c  

 13ln43e5x+c-\frac{1}{3}\ln\left|4-3e^{5x}\right|+c  

 15e5xln43e5x+c-15e^{5x}\ln\left|4-3e^{5x}\right|+c  

 3e5xln43e5x+c-3e^{5x}\ln\left|4-3e^{5x}\right|+c  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 32xdx\int3^{2x}dx  

 32x2ln 3+c\frac{3^{2x}}{2\ln\ 3}+c  

 (2ln 3 )32x+c\left(2\ln\ 3\ \right)3^{2x}+c  

 12ln32x+c\frac{1}{2}\ln3^{2x}+c  

 232x+c2\cdot3^{2x}+c  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 5(2x24x)(x1)dx\int5^{\left(2x^2-4x\right)}\left(x-1\right)dx  

 14ln55(2x24x)+c\frac{1}{4\ln5}5^{\left(2x^2-4x\right)}+c  

 (14ln5)5(2x24x)+c\left(\frac{1}{4}\ln5\right)5^{\left(2x^2-4x\right)}+c  

 (4ln5)(x1)5(23x32x2)+c\left(4\ln5\right)\left(x-1\right)5^{\left(\frac{2}{3}x^3-2x^2\right)}+c  

 (ln5)(23x32x2)+c\left(\ln5\right)\left(\frac{2}{3}x^3-2x^2\right)+c  

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