B L → = − = − \overrightarrow{BL}=_-=_- B L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − = − Usando as letras da figura completa:

A K → e E O → \overrightarrow{AK}\ e\ \overrightarrow{EO} A K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e E O <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

B G → e J O → \overrightarrow{BG}\ e\ \overrightarrow{JO} B G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e J O <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

O P → e K J → \overrightarrow{OP}\ e\ \overrightarrow{KJ} O P <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e K J <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

H G → e J F → \overrightarrow{HG}\ e\ \overrightarrow{JF} H G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> e J F <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

I K → + I M → = − \overrightarrow{IK}\ +\overrightarrow{IM}=_- I K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + I M <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

I O → \overrightarrow{IO} I O <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

O I → \overrightarrow{OI} O I <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

G L → \overrightarrow{GL} G L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K M → \overrightarrow{KM} K M <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

C D → + D L → = − \overrightarrow{CD}\ +\overrightarrow{DL}=_- C D <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + D L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

C L → \overrightarrow{CL} C L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

L C → \overrightarrow{LC} L C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

O L → \overrightarrow{OL} O L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

I J → + K C → = − \overrightarrow{IJ}\ +\overrightarrow{KC}=_- I J <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + K C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

J C → \overrightarrow{JC} J C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

J G → \overrightarrow{JG} J G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K N → \overrightarrow{KN} K N <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

I C → \overrightarrow{IC} I C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A C → + C A → = − \overrightarrow{AC}+\overrightarrow{CA}=_- A C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + C A <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A C → \overrightarrow{AC} A C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

C A → \overrightarrow{CA} C A <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

− A C → -\overrightarrow{AC} − A C <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

M N → + P M → = − \overrightarrow{MN}+\overrightarrow{PM}=_- M N <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + P M <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

P N → \overrightarrow{PN} P N <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

J L → \overrightarrow{JL} J L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

D G → \overrightarrow{DG} D G <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A F → \overrightarrow{AF} A F <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A K → + L B → = − \overrightarrow{AK}+\overrightarrow{LB}=_- A K <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> + L B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" /> = − Usando as letras da figura completa:

0 → \overrightarrow{0} 0 <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K B → \overrightarrow{KB} K B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

K L → \overrightarrow{KL} K L <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

A B → \overrightarrow{AB} A B <path d="M 0 241 v 40 h 399891 c -47.3 35.3 -84 78 -110 128 c -16.7 32 -27.7 63.7 -33 95 c 0 1.3 -0.2 2.7 -0.5 4 c -0.3 1.3 -0.5 2.3 -0.5 3 c 0 7.3 6.7 11 20 11 c 8 0 13.2 -0.8 15.5 -2.5 c 2.3 -1.7 4.2 -5.5 5.5 -11.5 c 2 -13.3 5.7 -27 11 -41 c 14.7 -44.7 39 -84.5 73 -119.5 s 73.7 -60.2 119 -75.5 c 6 -2 9 -5.7 9 -11 s -3 -9 -9 -11 c -45.3 -15.3 -85 -40.5 -119 -75.5 s -58.3 -74.8 -73 -119.5 c -4.7 -14 -8.3 -27.3 -11 -40 c -1.3 -6.7 -3.2 -10.8 -5.5 -12.5 c -2.3 -1.7 -7.5 -2.5 -15.5 -2.5 c -14 0 -21 3.7 -21 11 c 0 2 2 10.3 6 25 c 20.7 83.3 67 151.7 139 205 Z m 0 0 v 40 h 399900 v -40 Z" />

8º ano vetores 1

Quiz

•

Mathematics

•

1st - 4th Grade

•

Practice Problem

•

Hard

Susana Silva

Used 22+ times

FREE Resource

G

P

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

16 questions

Figuras bidimensionales

Quiz

•

1st Grade

10 questions

Olimpiada MATEMÀTICA CSDB

Quiz

•

2nd Grade

8 questions

Números hasta 999

Quiz

•

1st Grade

12 questions

Fracciones

Quiz

•

4th Grade

10 questions

CUADRILATEROS.

Quiz

•

4th Grade

15 questions

Quadrilateri

Quiz

•

4th Grade

$Identificación de fracciones$

15 questions

Identificación de fracciones

Quiz

•

3rd - 5th Grade

15 questions

Clasificación de Ángulos

Quiz

•

4th Grade

Popular Resources on Wayground

10 questions

Honoring the Significance of Veterans Day

Interactive video

•

6th - 10th Grade

9 questions

FOREST Community of Caring

Lesson

•

1st - 5th Grade

10 questions

Exploring Veterans Day: Facts and Celebrations for Kids

Interactive video

•

6th - 10th Grade

19 questions

Veterans Day

Quiz

•

5th Grade

14 questions

General Technology Use Quiz

Quiz

•

8th Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

15 questions

Circuits, Light Energy, and Forces

Quiz

•

5th Grade

19 questions

Thanksgiving Trivia

Quiz

•

6th Grade

Discover more resources for Mathematics

10 questions

Area

Quiz

•

3rd Grade

21 questions

Factors and Multiples

Quiz

•

4th Grade

20 questions

Division Facts

Quiz

•

3rd Grade

10 questions

multiplication facts

Quiz

•

3rd Grade

20 questions

Multiplication Facts

Quiz

•

3rd Grade

20 questions

Multiplication and Division Fact Families

Quiz

•

3rd Grade

30 questions

Multiplication Facts

Quiz

•

3rd Grade

20 questions

multiplication and division facts

Quiz

•

3rd Grade

8º ano vetores 1

11 questions

$\overrightarrow{BL}=_-=_-$
Usando as letras da figura completa:

$A+\overrightarrow{BC}=_-$
Usando as letras da figura completa:

$\overrightarrow{IK}\ +\overrightarrow{IM}=_-$
Usando as letras da figura completa:

$\overrightarrow{CD}\ +\overrightarrow{DL}=_-$
Usando as letras da figura completa:

$\overrightarrow{IJ}\ +\overrightarrow{KC}=_-$
Usando as letras da figura completa:

$J+\overrightarrow{JL}=_-$
Usando as letras da figura completa:

$G+\overrightarrow{GM}=_-$
Usando as letras da figura completa:

$\overrightarrow{AC}+\overrightarrow{CA}=_-$
Usando as letras da figura completa

$\overrightarrow{MN}+\overrightarrow{PM}=_-$
Usando as letras da figura completa:

$\overrightarrow{AK}+\overrightarrow{LB}=_-$
Usando as letras da figura completa:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

8º ano vetores 1

11 questions

BL→=−=−\overrightarrow{BL}=_-=_-BL=−​=−​ Usando as letras da figura completa:

A+BC→=−A+\overrightarrow{BC}=_-A+BC=−​ Usando as letras da figura completa:

IK→ +IM→=−\overrightarrow{IK}\ +\overrightarrow{IM}=_-IK +IM=−​ Usando as letras da figura completa:

CD→ +DL→=−\overrightarrow{CD}\ +\overrightarrow{DL}=_-CD +DL=−​ Usando as letras da figura completa:

IJ→ +KC→=−\overrightarrow{IJ}\ +\overrightarrow{KC}=_-IJ +KC=−​ Usando as letras da figura completa:

J+JL→=−J+\overrightarrow{JL}=_-J+JL=−​ Usando as letras da figura completa:

G+GM→=−G+\overrightarrow{GM}=_-G+GM=−​ Usando as letras da figura completa:

AC→+CA→=−\overrightarrow{AC}+\overrightarrow{CA}=_-AC+CA=−​ Usando as letras da figura completa

MN→+PM→=−\overrightarrow{MN}+\overrightarrow{PM}=_-MN+PM=−​ Usando as letras da figura completa:

AK→+LB→=−\overrightarrow{AK}+\overrightarrow{LB}=_-AK+LB=−​ Usando as letras da figura completa:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

$\overrightarrow{BL}=_-=_-$
Usando as letras da figura completa:

$A+\overrightarrow{BC}=_-$
Usando as letras da figura completa:

$\overrightarrow{IK}\ +\overrightarrow{IM}=_-$
Usando as letras da figura completa:

$\overrightarrow{CD}\ +\overrightarrow{DL}=_-$
Usando as letras da figura completa:

$\overrightarrow{IJ}\ +\overrightarrow{KC}=_-$
Usando as letras da figura completa:

$J+\overrightarrow{JL}=_-$
Usando as letras da figura completa:

$G+\overrightarrow{GM}=_-$
Usando as letras da figura completa:

$\overrightarrow{AC}+\overrightarrow{CA}=_-$
Usando as letras da figura completa

$\overrightarrow{MN}+\overrightarrow{PM}=_-$
Usando as letras da figura completa:

$\overrightarrow{AK}+\overrightarrow{LB}=_-$
Usando as letras da figura completa: