Midpoint & Distance Formula Review

Midpoint & Distance Formula Review

10th Grade

15 Qs

quiz-placeholder

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Midpoint & Distance Formula Review

Midpoint & Distance Formula Review

Assessment

Quiz

Mathematics

10th Grade

Medium

CCSS
HSG.GPE.B.6, HSG.GPE.B.7, 5.G.A.1

+3

Standards-aligned

Created by

Bonnie Negrich

Used 29+ times

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Which of the following is the correct midpoint formula given two endpoints (x1, y1) and (x2, y2)?

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSG.GPE.B.6

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is the midpoint of the segment with endpoints (1, 9) and (-3, 5)?

(-1, 7)

(2, 7)

(7, -1)

(2, 2)

Tags

CCSS.HSG.GPE.B.6

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image
Find the y-coordinate of the midpoint of the line
1
2
-2
3

Tags

CCSS.HSG.GPE.B.6

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

How is finding the length of segment AB written in the distance formula?


d = (53)2 + (02)2d\ =\ \sqrt{\left(5-3\right)^2\ +\ \left(0--2\right)^2}

d = (25)2 + (3 0)2d\ =\ \sqrt{\left(2-5\right)^2\ +\ \left(3\ -0\right)^2}

d = (53)2 (02)2d\ =\ \sqrt{\left(5-3\right)^2\ -\ \left(0--2\right)^2}

d = (43)2 (24)2d\ =\ \sqrt{\left(4-3\right)^2\ -\ \left(2-4\right)^2}

Tags

CCSS.HSG.GPE.B.7

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image
On the coordinate plane, which line is the y-axis?
Horizontal Line (Side to Side)
Vertical Line (Up and Down)

Tags

CCSS.5.G.A.1

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image
What letter is at (7, -6)?
D
L
X
There is no letter at those coordinates.

Tags

CCSS.5.G.A.2

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

How is the distance formula correctly written:

d = (y1 y2)2 (x2 x1)2 d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\

d = (x2 x1)2 + (y2 y1 )2d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)^2}

d = (y1 y2)2 + (x2 x1)2d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)^2}

d = (x)2 (y)2\sqrt{\left(x\right)^2-\ \left(y\right)^2}

Tags

CCSS.HSG.GPE.B.7

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