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Fungsi Naik dan Fungsi Turun Fungsi Trigonometri

Authored by Wahyu Prasetyo Wibowo

Mathematics

12th Grade

CCSS covered

Used 61+ times

Fungsi Naik dan Fungsi Turun Fungsi Trigonometri
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8 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Suatu fungsi dikatakan fungsi naik jika ..

f(x)>0f\left(x\right)>0

f(x)<0f'\left(x\right)<0

f(x)<0f\left(x\right)<0

f(x)>0f'\left(x\right)>0

f(x)=0f'\left(x\right)=0

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Fungsi f(x) dinyatakan akan turun apabila ... .

f'(x) > 0

f'(x) < 0

f'(x) = 0

f'(x)  \le   0

f'(x)  \ge   0

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

interval fungsi naik pada fungsi trigonometri y = sin x + cos x, untuk 0o < x < 360o adalah....

0o < x < 45o dan 225o < x < 360o.

45o < x < 225o

0o < x < 45o saja

225o < x < 360o.saja

0o < x < 225o

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diberikan fungsi  f(x)=2+sin3x, 0°x360°f\left(x\right)=2+\sin3x,\ 0\degree\le x\le360\degree  . Fungsi tersebut naik pada interval ...

 30°<x<90° 30\degree<x<90\degree\   

 0°x<30° 0\degree\le x<30\degree\   

 150°<x<210°150\degree<x<210\degree  

 270°<x<330°270\degree<x<330\degree  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Grafik y = sin x + cos x akan naik pada interval

0 < x < π/4

π/4 < x < π

π < x < 5π/4

π < x < 2π

0 < x < 2π

Tags

CCSS.HSF.TF.A.4

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Fungsi

 f(x)=cos(xπ3)f\left(x\right)=\cos\left(x-\frac{\pi}{3}\right)  , untuk  0<x<2π0<x<2\pi  , turun pada interval ...

 0<x<π30<x<\frac{\pi}{3}  

 π3<x<π\frac{\pi}{3}<x<\pi  

 π<x<4π3\pi<x<\frac{4\pi}{3}  

 0<x<π0<x<\pi  

 π3<x<4π3\frac{\pi}{3}<x<\frac{4\pi}{3}  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui fungsi g(x)=cos(xπ3)g\left(x\right)=\cos\left(x-\frac{\pi}{3}\right)  untuk  0x2π0\le x\le2\pi  . Fungsi  gg  naik pada interval ....


 0xπ30\le x\le\frac{\pi}{3}  

 π3x4π3\frac{\pi}{3}\le x\le\frac{4\pi}{3}  

 π2xπ\frac{\pi}{2}\le x\le\pi  

 0xπ3 dan 4π3x2π 0\le x\le\frac{\pi}{3}\ dan\ \frac{4\pi}{3}\le x\le2\pi\   

 0xπ2 dan 2π3x2π0\le x\le\frac{\pi}{2}\ dan\ \frac{2\pi}{3}\le x\le2\pi  

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