Interval Notation

Write x > -4

using interval notation.

• (-∞, -4)

• (∞, -4)

• (-4, ∞)

• (-4, -∞)

Tags

CCSS.6.EE.B.8

Write x ≤ 10

using interval notation:

• (-∞, 10]

• (-∞, 10)

• [10, ∞)

• (10, ∞)

Tags

CCSS.6.EE.B.8

Write x ≥ 0

using interval notation:

• (∞, 0)

• (0, ∞)

• (∞, 0]

• [0, ∞)

Tags

CCSS.6.EE.B.8

Write x < 3

using interval notation:

• (-∞, 3]

• (-∞, 3)

• (3, -∞)

• [3, -∞)

Tags

CCSS.6.EE.B.8

Interpret (-3, ∞)

• x < -3

• x ≤ -3

• x ≥ -3

• x > -3

Tags

CCSS.6.EE.B.8

Interpret (-∞, 5]

• x < 5

• x ≤ 5

• x > 5

• x ≥ 5

Tags

CCSS.6.EE.B.8

Interpret [-4, ∞)

• x > -4

• x < -4

• x ≥ -4

• x ≤ -4

Tags

CCSS.6.EE.B.8

The syllabus you received at

orientation listed a graphing calculator (TI-84 or similar) as a

required supply for this class.

Have you already purchased yours?

• Yes

• No

Tags

CCSS.HSF-IF.C.7E

What is the first step in

solving this equation?

4|2 - v| - 3 = 25

• Distribute the 4

• Add 3 to both sides

• Divide both sides by 4

• Write two equations;

  one set = 25 and the other set = -25

Rewrite for h:

 $A\ =\ \frac{1}{2}h\left(b_1+b_2\right)$  

•  $h=2A\ -b_1-b_2$  

•  $h=\frac{A}{2\left(b_1+b_2\right)}$  

•  $h\ =\frac{2A}{b_1+b_2}$  

•  $h=\frac{2A}{-b_1-b_2}$  

Tags

CCSS.HSA.CED.A.4