DEUST 1_1Eq_Deg2

DEUST 1_1Eq_Deg2

10th Grade

5 Qs

quiz-placeholder

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DEUST 1_1Eq_Deg2

DEUST 1_1Eq_Deg2

Assessment

Quiz

Mathematics

10th Grade

Hard

Created by

Roland MAGRE

Used 5+ times

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Résoudre :

 x2 + 3x + 1 = 0x^2\ +\ 3x\ +\ 1\ =\ 0  

 S = {(3 + 5)2; (3   5)2}S\ =\ \left\{\frac{\left(-3\ +\ \sqrt{5}\right)}{2};\ \frac{\left(-3\ \ -\ \sqrt{5}\right)}{2}\right\}  

  S = {(3 + 5)2; (3   5)2}\ S\ =\ \left\{\frac{\left(-3\ +\ \sqrt{5}\right)}{2};\ \frac{\left(3\ \ -\ \sqrt{5}\right)}{2}\right\}  

 S =  {(3 + 5)2; (3   5)2}S\ =\ \ \left\{\frac{\left(3\ +\ \sqrt{5}\right)}{2};\ \frac{\left(3\ \ -\ \sqrt{5}\right)}{2}\right\}  

 S =  {(3 + 5)2; (3  + 5)2}S\ =\ \ \left\{\frac{\left(3\ +\ \sqrt{5}\right)}{-2};\ \frac{\left(3\ \ +\ \sqrt{5}\right)}{2}\right\}  

Je passe

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Résoudre x2 + 6x + 1 = 0 -x^2\ +\ 6x\ +\ 1\ =\ 0\   

 S = ϕS\ =\ \phi  

 S = { 0}S\ =\ \left\{\ 0\right\}  

 S = { 3 + 10 ; 3 + 10 }S\ =\ \left\{-\ 3\ +\ \sqrt{10}\ ;\ 3\ +\ \sqrt{10}\ \right\}  

 S = {3 + 10 ; 3  10}S\ =\ \left\{3\ +\ \sqrt{10}\ ;\ 3\ -\ \sqrt{10}\right\}  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 x2  2x + 2 = 0x^2\ -\ 2x\ +\ 2\ =\ 0  

 S = { 0 }S\ =\ \left\{\ 0\ \right\}  

 S = ϕS\ =\ \phi  

 S = {2 ; 2 }S\ =\ \left\{-2\ ;\ 2\ \right\}  

 S = {12 ; 12}S\ =\ \left\{\frac{1}{2}\ ;\ -\frac{1}{2}\right\}  

Je passe

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Résoudre :

 x2  2x + 1 = 0x^2\ -\ 2x\ +\ 1\ =\ 0  

 S = { 0 }S\ =\ \left\{\ 0\ \right\}  

 S = ϕS\ =\ \phi  

 S = { 1 }S\ =\ \left\{\ 1\ \right\}  

 S = { 1 }S\ =\ \left\{\ -1\ \right\}  

Je passe

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Résoudre

 5x2  2x  6 = 05x^2\ -\ 2x\ -\ 6\ =\ 0  

 S = {(1+31)5 ; (1 + 31)5}S\ =\ \left\{\frac{\left(1+\sqrt{31}\right)}{5}\ ;\ \frac{\left(1\ +\ \sqrt{31}\right)}{-5}\right\}  

 S = {(1+31)5 ; (1  31)5}S\ =\ \left\{\frac{\left(1+\sqrt{31}\right)}{5}\ ;\ \frac{\left(1\ -\ \sqrt{31}\right)}{5}\right\}  

 S = {(1+31)5 ; (1  31)5}S\ =\ \left\{\frac{\left(-1+\sqrt{31}\right)}{5}\ ;\ \frac{\left(-1\ -\ \sqrt{31}\right)}{5}\right\}  

 S = ϕS\ =\ \phi  

Je passe