OBLIQUE TRIANGLES

OBLIQUE TRIANGLES

9th - 10th Grade

10 Qs

quiz-placeholder

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OBLIQUE TRIANGLES

OBLIQUE TRIANGLES

Assessment

Quiz

Mathematics

9th - 10th Grade

Hard

CCSS
HSG.SRT.D.11, HSG.SRT.D.10, HSG.CO.C.11

Standards-aligned

Created by

MARITES BERAN

Used 14+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Media Image

Which law would you need to solve the given problem?

Law of Sines

Law of Cosines

Both

Neither

Tags

CCSS.HSG.SRT.D.11

CCSS.HSG.SRT.D.10

2.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

To solve triangle ABC, where a = 5, b = 6, c = 7. Which of the following would you need to use first?

Law of Sines

Law of Cosines

Pythagorean Theorem

None of the above

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

Find the value of side AB.

27.99 units

21.74 units

18.84 units

13.59 units

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

If C = 135°, a = 52, and A = 30°, what is the value of c?

52

52252\sqrt{2}

5263\frac{52\sqrt{6}}{3}

26326\sqrt{3}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

5.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Media Image

Which of the following would you use to find the length of AC using Sine Rule?

sin 51.381°=sin AC85°\frac{\sin\ 51.3}{81\degree}=\frac{\sin\ AC}{85\degree}

51.3sin 81°=sin 85°AC\frac{51.3}{\sin\ 81\degree}=\frac{\sin\ 85\degree}{AC}

51.3sin 81°=ACsin 85°\frac{51.3}{\sin\ 81\degree}=\frac{AC}{\sin\ 85\degree}

51.3sin 85°=ACsin 81°\frac{51.3}{\sin\ 85\degree}=\frac{AC}{\sin\ 81\degree}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which of the following is the correct formula to find the measure of angle A?

 cos1 a2+b2c22ab\cos^{-1}\ \frac{a^2+b^2-c^2}{2ab}  

 cos1 b2+c2a22bc\cos^{-1}\ \frac{b^2+c^2-a^2}{2bc} 

 cos1 a2+b2c22ab\cos^{-1}\ \frac{a^2+b^2-c^2}{2ab} 

 cos1 a2+c2b22ac\cos^{-1}\ \frac{a^2+c^2-b^2}{2ac} 

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

7.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Media Image

What is the length of PR?

PR2=9.2+8.5(9.2)(8.5)cos 89°PR^2=9.2+8.5-\left(9.2\right)\left(8.5\right)\cos\ 89\degree

PR2=9.22+8.52(9.2)2(8.5)2cos 89°PR^2=9.2^2+8.5^2-\left(9.2\right)^2\left(8.5\right)^2\cos\ 89\degree

PR2=9.22+8.522(9.2)(8.5)cos 89°PR^2=9.2^2+8.5^2-2\left(9.2\right)\left(8.5\right)\cos\ 89\degree

PR2=9.22+8.52+2(9.2)(8.5)cos 89°PR^2=9.2^2+8.5^2+2\left(9.2\right)\left(8.5\right)\cos\ 89\degree

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

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