Search Header Logo

OBLIQUE TRIANGLES

Authored by MARITES BERAN

Mathematics

9th - 10th Grade

CCSS covered

Used 14+ times

OBLIQUE TRIANGLES
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Media Image

Which law would you need to solve the given problem?

Law of Sines

Law of Cosines

Both

Neither

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

2.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

To solve triangle ABC, where a = 5, b = 6, c = 7. Which of the following would you need to use first?

Law of Sines

Law of Cosines

Pythagorean Theorem

None of the above

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

Find the value of side AB.

27.99 units

21.74 units

18.84 units

13.59 units

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

If C = 135°, a = 52, and A = 30°, what is the value of c?

52

52252\sqrt{2}

5263\frac{52\sqrt{6}}{3}

26326\sqrt{3}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

5.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Media Image

Which of the following would you use to find the length of AC using Sine Rule?

sin 51.381°=sin AC85°\frac{\sin\ 51.3}{81\degree}=\frac{\sin\ AC}{85\degree}

51.3sin 81°=sin 85°AC\frac{51.3}{\sin\ 81\degree}=\frac{\sin\ 85\degree}{AC}

51.3sin 81°=ACsin 85°\frac{51.3}{\sin\ 81\degree}=\frac{AC}{\sin\ 85\degree}

51.3sin 85°=ACsin 81°\frac{51.3}{\sin\ 85\degree}=\frac{AC}{\sin\ 81\degree}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which of the following is the correct formula to find the measure of angle A?

 cos1 a2+b2c22ab\cos^{-1}\ \frac{a^2+b^2-c^2}{2ab}  

 cos1 b2+c2a22bc\cos^{-1}\ \frac{b^2+c^2-a^2}{2bc} 

 cos1 a2+b2c22ab\cos^{-1}\ \frac{a^2+b^2-c^2}{2ab} 

 cos1 a2+c2b22ac\cos^{-1}\ \frac{a^2+c^2-b^2}{2ac} 

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

7.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Media Image

What is the length of PR?

PR2=9.2+8.5(9.2)(8.5)cos 89°PR^2=9.2+8.5-\left(9.2\right)\left(8.5\right)\cos\ 89\degree

PR2=9.22+8.52(9.2)2(8.5)2cos 89°PR^2=9.2^2+8.5^2-\left(9.2\right)^2\left(8.5\right)^2\cos\ 89\degree

PR2=9.22+8.522(9.2)(8.5)cos 89°PR^2=9.2^2+8.5^2-2\left(9.2\right)\left(8.5\right)\cos\ 89\degree

PR2=9.22+8.52+2(9.2)(8.5)cos 89°PR^2=9.2^2+8.5^2+2\left(9.2\right)\left(8.5\right)\cos\ 89\degree

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?