PEMDAS Rule

 $\left(6+3\times5\right)\ -\ \left(10-3\times3\right)=$  

 $3^{3\ }\div3\ +\ 15\ =\$  

 $\left(2^3+4+12\right)\div6\ =$  

 $100\ +45\div9\times40=$  

 $45\div\left(3\ +2\right)+12\ =$  

 $8\ +\left(8\div8\right)\times8\ =\$  

 $3+20\div4\times2=$  

 $\left(7^2-14\ +20\right)\times2\ =\$  

 $\left(63\div9\right)-\left(2+5\right)=$  

 $20\ -\ \left(5\times3\right)\ +2=$