Basic Geometric Proofs
Authored by Leslie Curfew
Mathematics
10th Grade
CCSS covered
Used 11+ times
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37 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: AC = AB + AB
Prove: AB = BC
Reason 1: Given
What is Step 1?
Tags
CCSS.HSG.CO.C.10
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
What is the justification for Step 1?
Tags
CCSS.HSG.SRT.B.5
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
What is the justification for Step 2?
Tags
CCSS.HSG.SRT.B.5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
What is the justification for Step 3?
Tags
CCSS.7.G.B.5
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
What is the justification for Step 4?
Tags
CCSS.HSG.SRT.B.5
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
What is the justification for Step 5?
Tags
CCSS.HSG.SRT.B.5
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
What is the justification for Step 6?
Tags
CCSS.HSG.SRT.B.5
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