QQuadratics: Factorisation and Completing the Square

(3x - 8)(3x + 8) is the result of factorising:

•  $9x^2+64$  

•  $9x^2\text{+48x+64}$  

•   $9x^2-48x+64$  

•  $9x^2-64$  

When

 $\left(x+4\right)^2-25\$  is factorised and simplified, the result is:

• (x-9)(x+1)

• (x-5)(x+5)

• (x-1)(x+9)

• (x+1)(x+9)

When fully factorised,

 $3x^2-\ 147$  equals:

• (3x - 49)(x + 3)

• 3(x + 7)(x - 7)

• (x - 7)(x + 7)

• 3(x - 7)(x - 7)

(x + 5)(x - 6) is the result when one of the following is factorised:

• $x^2\ +\ 11x\ +\ 30$

• $x^2\ +\ x\ -30$

• $x^{2\ }-\ 11x\ -\ 30$

• $x^2\ -\ x\ -\ 30$

 $\ x^2\ -\ 15x\ +\ 36$ when factorised equals:

• (x - 4)(x - 9)

• (x - 6)(x - 6)

• (x - 3)(x - 12)

• (x - 2)(x - 18)

When you factorise

 $x^2\ +\ 13x\ -\ 30$  the result is:

• (x + 15)(x - 2)

• (x - 15)(x + 2)

• (x + 3)(x + 10)

• (x - 3)(x - 10)

(3x - 5)(x - 3) is the factorisation of:

• $3x^2\ +\ 14x\ +15$

• $3x^2\ -\ 14x\ -\ 15$

• $3x^2-\ 8x\ +15$

• $3x^2\ -\ 14x\ +\ 15$

If I complete the square for

 $x^2\ +\ 8x\ +\ 12$  the coefficient of x has to be:

• doubled then squared

• squared then halved

• halved then squared

• squared then doubled

What value of c would make this a perfect square trinomial?

x² +8x + c

• 4

• 16

• 64

• -16

What value of c would make this a perfect square?

x² - 12x + c

• 36

• 24

• 144

• -36