Tentukan penyelesaian persamaan 2 sin ⁡ x − 2 = 0 2\ \sin\ x\ -\ \sqrt{2}=0 2 sin x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 0 untuk 0 ≤ x ≤ 2 π 0\ \le x\le2\pi 0 ≤ x ≤ 2 π

π 4 a t a u 3 π 4 \frac{\pi}{4}\ atau\ \frac{3\pi}{4} 4 π a t a u 4 3 π

3 π 4 a t a u 5 π 4 \frac{3\pi}{4}\ atau\ \frac{5\pi}{4} 4 3 π a t a u 4 5 π

π 6 a t a u 5 π 6 \frac{\pi}{6}\ atau\ \frac{5\pi}{6} 6 π a t a u 6 5 π

5 π 6 a t a u 7 π 6 \frac{5\pi}{6}\ atau\ \frac{7\pi}{6} 6 5 π a t a u 6 7 π

− π 4 a t a u 3 π 4 -\frac{\pi}{4}\ atau\ \frac{3\pi}{4} − 4 π a t a u 4 3 π

Tentukan himpunan penyelesaian persamaan 2 sin ⁡ ( x + 15 ) ° = 1 \sqrt{2}\sin\left(x+15\right)\degree\ =\ 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> sin ( x + 1 5 ) ° = 1 untuk 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 °

30 ° a t a u 120 ° 30\degree\ atau\ 120\degree 3 0 ° a t a u 1 2 0 °

45 ° a t a u 135 ° 45\degree\ atau\ 135\degree 4 5 ° a t a u 1 3 5 °

60 ° a t a u 210 ° 60\degree\ atau\ 210\degree 6 0 ° a t a u 2 1 0 °

120 ° a t a u 240 ° 120\degree\ atau\ 240\degree 1 2 0 ° a t a u 2 4 0 °

45 ° a t a u 120 ° 45\degree\ atau\ 120\degree 4 5 ° a t a u 1 2 0 °

Penyelesaian persamaan sin ⁡ x = 1 2 2 \sin\ x=\frac{1}{2}\sqrt{2\ } sin x = 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> untuk 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 ° adalah . . .

x = 45 ° , 135 ° x=45\degree,\ 135\degree x = 4 5 ° , 1 3 5 °

x = 45 ° , 225 ° x=45\degree,\ 225\degree x = 4 5 ° , 2 2 5 °

x = 45 ° , 315 ° x=45\degree,\ 315\degree x = 4 5 ° , 3 1 5 °

x = 135 ° , 225 ° x=135\degree,\ 225\degree x = 1 3 5 ° , 2 2 5 °

x = 225 ° , 315 ° x=225\degree,\ 315\degree x = 2 2 5 ° , 3 1 5 °

\ Tentukan Penyelesaian Persamaan 2 cos ⁡ ( x − 20 ) ° + 1 = 0 2\ \cos\ \left(x-20\right)\degree\ +1=0 2 cos ( x − 2 0 ) ° + 1 = 0 untuk 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 °

{ 140 ° , 260 ° } \left\{140\degree,260\degree\right\} { 1 4 0 ° , 2 6 0 ° }

{ 130 ° , 240 ° } \left\{130\degree,240\degree\right\} { 1 3 0 ° , 2 4 0 ° }

{ 150 ° , 270 ° } \left\{150\degree,270\degree\right\} { 1 5 0 ° , 2 7 0 ° }

{ 120 ° , 260 ° } \left\{120\degree,260\degree\right\} { 1 2 0 ° , 2 6 0 ° }

{ 140 ° , 240 ° } \left\{140\degree,240\degree\right\} { 1 4 0 ° , 2 4 0 ° }

Tentukan Himpunan Penyelesaian persamaan 2 cos ⁡ 1 2 x − 3 = 0 2\ \cos\ \frac{1}{2}x\ -\sqrt{3}=0 2 cos 2 1 x − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 0 untuk 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 °

120 ° a t a u 240 ° 120\degree\ atau\ 240\degree 1 2 0 ° a t a u 2 4 0 °

150 ° a t a u 330 ° 150\degree\ atau\ 330\degree 1 5 0 ° a t a u 3 3 0 °

60 ° a t a u 240 ° 60\degree\ atau\ 240\degree 6 0 ° a t a u 2 4 0 °

120 ° a t a u 210 ° 120\degree\ atau\ 210\degree 1 2 0 ° a t a u 2 1 0 °

150 ° a t a u 240 ° 150\degree\ atau\ 240\degree 1 5 0 ° a t a u 2 4 0 °

Himpunan penyelesaian persamaan cos 2x = cos 6 0 ° 60^{\degree} 6 0 ° pada interval 0 ° ≤ x ≤ 36 0 ° 0^{\degree}\le x\le360^{\degree} 0 ° ≤ x ≤ 3 6 0 ° adalah...

{ 3 0 ° , 24 0 ° } \left\{30^{\degree},\ 240^{\degree}\right\} { 3 0 ° , 2 4 0 ° }

{ 6 0 ° , 24 0 ° } \left\{60^{\degree},240^{\degree}\right\} { 6 0 ° , 2 4 0 ° }

{ 3 0 ° , 6 0 ° , 21 0 ° } \left\{30^{\degree},\ 60^{\degree},210^{\degree}\right\} { 3 0 ° , 6 0 ° , 2 1 0 ° }

\ Himpunan penyelesaian dari tan ⁡ ⁡ x = tan ⁡ ⁡ ( 3 5 π ) \tan⁡x=\tan⁡\left(\frac{3}{5}\pi\right) tan ⁡ x = tan ⁡ ( 5 3 π ) untuk 0 ° ≤ x ≤ 2 π 0°≤x≤2π 0 ° ≤ x ≤ 2 π adalah . . .

{ 3 5 π , 8 5 π } \left\{\frac{3}{5}π,\ \frac{8}{5}π\right\} { 5 3 π , 5 8 π }

{ 3 5 π , 7 5 π } \left\{\frac{3}{5}π,\ \frac{7}{5}π\right\} { 5 3 π , 5 7 π }

{ 3 5 π , 9 5 π } \left\{\frac{3}{5}π,\ \frac{9}{5}π\right\} { 5 3 π , 5 9 π }

{ 3 5 π , 13 5 π } \left\{\frac{3}{5}π,\ \frac{13}{5}π\right\} { 5 3 π , 5 1 3 π }

{ 3 5 π , 11 5 π } \left\{\frac{3}{5}π,\ \frac{11}{5}π\right\} { 5 3 π , 5 1 1 π }

Himpunan penyelesaian dari tan ⁡ ⁡ ( x + 25 ° ) = tan ⁡ ⁡ 50 ° \tan⁡(x+25°)=\tan⁡50° tan ⁡ ( x + 2 5 ° ) = tan ⁡ 5 0 ° untuk 0 ° ≤ x ≤ 360 ° 0°≤x≤360° 0 ° ≤ x ≤ 3 6 0 ° adalah . . .

{ 25 ° , 205 ° } \left\{25°,205°\right\} { 2 5 ° , 2 0 5 ° }

{ 25 ° , 105 ° } \left\{25°,105°\right\} { 2 5 ° , 1 0 5 ° }

{ 25 ° , 305 ° } \left\{25°,305°\right\} { 2 5 ° , 3 0 5 ° }

{ 75 ° , 105 ° } \left\{75°,105°\right\} { 7 5 ° , 1 0 5 ° }

{ 75 ° , 205 ° } \left\{75°,205°\right\} { 7 5 ° , 2 0 5 ° }

Tentukan Himpunan penyelesaian persamaan tan ⁡ x = 1 3 3 \tan\ x=\ \frac{1}{3}\sqrt{3} tan x = 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> untuk 0 ≤ x ≤ 2 π 0\ \le x\le2\pi 0 ≤ x ≤ 2 π

π 6 a t a u 7 π 6 \frac{\pi}{6}\ atau\ \frac{7\pi}{6} 6 π a t a u 6 7 π

− π 6 a t a u 7 π 6 -\frac{\pi}{6}\ atau\ \frac{7\pi}{6} − 6 π a t a u 6 7 π

π 6 a t a u − 7 π 6 \frac{\pi}{6}\ atau\ -\frac{7\pi}{6} 6 π a t a u − 6 7 π

− π 6 a t a u − 7 π 6 -\frac{\pi}{6}\ atau\ -\frac{7\pi}{6} − 6 π a t a u − 6 7 π

5 π 6 a t a u 7 π 6 \frac{5\pi}{6}\ atau\ \frac{7\pi}{6} 6 5 π a t a u 6 7 π

Penyelesaian dari cos x = − 1 2 3 -\frac{1}{2}\sqrt{3} − 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> dengan 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 ° adalah ....

x = 150 ° , 210 ° x=150\degree,\ 210\degree x = 1 5 0 ° , 2 1 0 °

x = 30 ° , 150 ° x=30\degree,\ 150\degree x = 3 0 ° , 1 5 0 °

x = 120 ° , 210 ° x=120\degree,\ 210\degree x = 1 2 0 ° , 2 1 0 °

x = 150 ° , 300 ° x=150\degree,\ 300\degree x = 1 5 0 ° , 3 0 0 °

x = 150 ° , 330 ° x=150\degree,\ 330\degree x = 1 5 0 ° , 3 3 0 °

PERSAMAAN TRIGONOMETRI

Authored by Deli Yusmanida

Mathematics

11th Grade

Used 146+ times

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

10 questions

Show all answers

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Tentukan penyelesaian persamaan $2\ \sin\ x\ -\ \sqrt{2}=0$ untuk $0\ \le x\le2\pi$

$\frac{3\pi}{4}\ atau\ \frac{5\pi}{4}$

$\frac{\pi}{6}\ atau\ \frac{5\pi}{6}$

$\frac{\pi}{4}\ atau\ \frac{3\pi}{4}$

$\frac{5\pi}{6}\ atau\ \frac{7\pi}{6}$

$-\frac{\pi}{4}\ atau\ \frac{3\pi}{4}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Tentukan himpunan penyelesaian persamaan $\sqrt{2}\sin\left(x+15\right)\degree\ =\ 1$ untuk $0\degree\le x\le360\degree$

$30\degree\ atau\ 120\degree$

$45\degree\ atau\ 135\degree$

$60\degree\ atau\ 210\degree$

$120\degree\ atau\ 240\degree$

$45\degree\ atau\ 120\degree$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Penyelesaian persamaan $\sin\ x=\frac{1}{2}\sqrt{2\ }$ untuk $0\degree\le x\le360\degree$ adalah . . .

$x=45\degree,\ 135\degree$

$x=45\degree,\ 225\degree$

$x=45\degree,\ 315\degree$

$x=135\degree,\ 225\degree$

$x=225\degree,\ 315\degree$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\$ Tentukan Penyelesaian Persamaan $2\ \cos\ \left(x-20\right)\degree\ +1=0$ untuk $0\degree\le x\le360\degree$

$\left\{130\degree,240\degree\right\}$

$\left\{150\degree,270\degree\right\}$

$\left\{120\degree,260\degree\right\}$

$\left\{140\degree,240\degree\right\}$

$\left\{140\degree,260\degree\right\}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Tentukan Himpunan Penyelesaian persamaan $2\ \cos\ \frac{1}{2}x\ -\sqrt{3}=0$ untuk $0\degree\le x\le360\degree$

$120\degree\ atau\ 240\degree$

$150\degree\ atau\ 330\degree$

$60\degree\ atau\ 240\degree$

$120\degree\ atau\ 210\degree$

$150\degree\ atau\ 240\degree$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Himpunan penyelesaian persamaan cos 2x = cos $60^{\degree}$ pada interval $0^{\degree}\le x\le360^{\degree}$ adalah...

$\left\{30^{\degree},\ 240^{\degree}\right\}$

$\left\{60^{\degree},240^{\degree}\right\}$

$\left\{30^{\degree},\ 60^{\degree},210^{\degree}\right\}$

$\left\{30^{\degree},\ 150^{\degree},\ 210^{\degree},\ 330^{\degree}\right\}$

$\left\{30^{\degree},\ 60^{\degree},\ 210^{\degree},\ 240^{\degree},\ 270^{\degree}\right\}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\$ Himpunan penyelesaian dari $\tan⁡x=\tan⁡\left(\frac{3}{5}\pi\right)$ untuk $0°≤x≤2π$ adalah . . .

$\left\{\frac{3}{5}π,\ \frac{7}{5}π\right\}$

$\left\{\frac{3}{5}π,\ \frac{8}{5}π\right\}$

$\left\{\frac{3}{5}π,\ \frac{9}{5}π\right\}$

$\left\{\frac{3}{5}π,\ \frac{13}{5}π\right\}$

$\left\{\frac{3}{5}π,\ \frac{11}{5}π\right\}$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Himpunan penyelesaian dari $\tan⁡(x+25°)=\tan⁡50°$ untuk $0°≤x≤360°$ adalah . . .

$\left\{25°,105°\right\}$

$\left\{25°,205°\right\}$

$\left\{25°,305°\right\}$

$\left\{75°,105°\right\}$

$\left\{75°,205°\right\}$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Tentukan Himpunan penyelesaian persamaan $\tan\ x=\ \frac{1}{3}\sqrt{3}$ untuk $0\ \le x\le2\pi$

$\frac{\pi}{6}\ atau\ \frac{7\pi}{6}$

$-\frac{\pi}{6}\ atau\ \frac{7\pi}{6}$

$\frac{\pi}{6}\ atau\ -\frac{7\pi}{6}$

$-\frac{\pi}{6}\ atau\ -\frac{7\pi}{6}$

$\frac{5\pi}{6}\ atau\ \frac{7\pi}{6}$

10.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Penyelesaian dari cos x = $-\frac{1}{2}\sqrt{3}$ dengan $0\degree\le x\le360\degree$ adalah ....

$x=30\degree,\ 150\degree$

$x=120\degree,\ 210\degree$

$x=150\degree,\ 210\degree$

$x=150\degree,\ 300\degree$

$x=150\degree,\ 330\degree$

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

15 questions

CAL_INT_2025A_C1

Quiz

•

11th Grade

15 questions

Lugares geométricos

Quiz

•

11th Grade

12 questions

Segundo Trimestre (repaso)

Quiz

•

4th - 12th Grade

9 questions

wielomiany -wstęp

Quiz

•

1st - 12th Grade

12 questions

INDEKS PECAHAN 3KZ

Quiz

•

5th - 12th Grade

13 questions

FUNÇÃO DO 1º E 2º GRAU

Quiz

•

10th - 11th Grade

12 questions

Prueba Unidad 6

Quiz

•

1st - 12th Grade

15 questions

StatProb Lesson 4 Quiz Reviewer (SY 23 - 24)

Quiz

•

11th Grade

Popular Resources on Wayground

10 questions

5.P.1.3 Distance/Time Graphs

Quiz

•

5th Grade

10 questions

Fire Drill

Quiz

•

2nd - 5th Grade

20 questions

Equivalent Fractions

Quiz

•

3rd Grade

15 questions

Hargrett House Quiz: Community & Service

Quiz

•

5th Grade

20 questions

Main Idea and Details

Quiz

•

5th Grade

20 questions

Context Clues

Quiz

•

6th Grade

20 questions

Inferences

Quiz

•

4th Grade

15 questions

Equivalent Fractions

Quiz

•

4th Grade

Discover more resources for Mathematics

16 questions

Identifying Angles

Quiz

•

7th - 12th Grade

15 questions

Exponential Growth and Decay Word Problems Practice

Quiz

•

9th - 12th Grade

20 questions

Central Angles and Arc Measures

Quiz

•

9th - 12th Grade

10 questions

Factor Quadratic Expressions with Various Coefficients

Quiz

•

9th - 12th Grade

30 questions

Intro to Circles Vocabulary

Quiz

•

9th - 12th Grade

19 questions

Explore Probability Concepts

Quiz

•

7th - 12th Grade

11 questions

Multiplying by 6

Quiz

•

KG - 12th Grade

29 questions

Scatterplots & Correlation Coefficients

Quiz

•

6th - 12th Grade

PERSAMAAN TRIGONOMETRI

Tentukan penyelesaian persamaan 2 sin⁡ x − 2=02\ \sin\ x\ -\ \sqrt{2}=02 sin x − 2​=0 untuk 0 ≤x≤2π0\ \le x\le2\pi0 ≤x≤2π

Tentukan himpunan penyelesaian persamaan 2sin⁡(x+15)° = 1\sqrt{2}\sin\left(x+15\right)\degree\ =\ 12​sin(x+15)° = 1 untuk 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360°

Penyelesaian persamaan sin⁡ x=122 \sin\ x=\frac{1}{2}\sqrt{2\ }sin x=21​2 ​ untuk 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360° adalah . . .

\ Tentukan Penyelesaian Persamaan 2 cos⁡ (x−20)° +1=02\ \cos\ \left(x-20\right)\degree\ +1=02 cos (x−20)° +1=0 untuk 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360°

Tentukan Himpunan Penyelesaian persamaan 2 cos⁡ 12x −3=02\ \cos\ \frac{1}{2}x\ -\sqrt{3}=02 cos 21​x −3​=0 untuk 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360°

Himpunan penyelesaian persamaan cos 2x = cos 60°60^{\degree}60° pada interval 0°≤x≤360°0^{\degree}\le x\le360^{\degree}0°≤x≤360° adalah...

\ Himpunan penyelesaian dari tan⁡⁡x=tan⁡⁡(35π)\tan⁡x=\tan⁡\left(\frac{3}{5}\pi\right)tan⁡x=tan⁡(53​π) untuk 0°≤x≤2π0°≤x≤2π0°≤x≤2π adalah . . .

Himpunan penyelesaian dari tan⁡⁡(x+25°)=tan⁡⁡50°\tan⁡(x+25°)=\tan⁡50°tan⁡(x+25°)=tan⁡50° untuk 0°≤x≤360°0°≤x≤360°0°≤x≤360° adalah . . .

Tentukan Himpunan penyelesaian persamaan tan⁡ x= 133\tan\ x=\ \frac{1}{3}\sqrt{3}tan x= 31​3​ untuk 0 ≤x≤2π0\ \le x\le2\pi0 ≤x≤2π

Penyelesaian dari cos x = −123-\frac{1}{2}\sqrt{3}−21​3​ dengan 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360° adalah ....

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Tentukan penyelesaian persamaan $2\ \sin\ x\ -\ \sqrt{2}=0$ untuk $0\ \le x\le2\pi$

Tentukan himpunan penyelesaian persamaan $\sqrt{2}\sin\left(x+15\right)\degree\ =\ 1$ untuk $0\degree\le x\le360\degree$

Penyelesaian persamaan $\sin\ x=\frac{1}{2}\sqrt{2\ }$ untuk $0\degree\le x\le360\degree$ adalah . . .

$\$ Tentukan Penyelesaian Persamaan $2\ \cos\ \left(x-20\right)\degree\ +1=0$ untuk $0\degree\le x\le360\degree$

Tentukan Himpunan Penyelesaian persamaan $2\ \cos\ \frac{1}{2}x\ -\sqrt{3}=0$ untuk $0\degree\le x\le360\degree$

Himpunan penyelesaian persamaan cos 2x = cos $60^{\degree}$ pada interval $0^{\degree}\le x\le360^{\degree}$ adalah...

$\$ Himpunan penyelesaian dari $\tan⁡x=\tan⁡\left(\frac{3}{5}\pi\right)$ untuk $0°≤x≤2π$ adalah . . .

Himpunan penyelesaian dari $\tan⁡(x+25°)=\tan⁡50°$ untuk $0°≤x≤360°$ adalah . . .

Tentukan Himpunan penyelesaian persamaan $\tan\ x=\ \frac{1}{3}\sqrt{3}$ untuk $0\ \le x\le2\pi$

Penyelesaian dari cos x = $-\frac{1}{2}\sqrt{3}$ dengan $0\degree\le x\le360\degree$ adalah ....