Ley del seno y coseno

Ley del seno y coseno

10th Grade

10 Qs

quiz-placeholder

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Ley del seno y coseno

Ley del seno y coseno

Assessment

Quiz

Mathematics

10th Grade

Hard

CCSS
HSG.SRT.D.10, 8.G.A.5, HSG.SRT.D.11

Standards-aligned

Created by

Leo Lopez

Used 78+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Para conocer el lado faltante del siguiente triángulo, es necesario aplicar

La ley seno

La ley coseno

Razones trigonométricas

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Para conocer uno de los ángulos del triángulo, tú piensas que:

Basta con aplicar la ley seno

Basta con aplicar la ley coseno

Basta aplicar el inverso de una función trigonométrica

No se puede determinar

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Para determinar la longitud del lado c, se debe aplicar:

La ley seno

La ley coseno

Ley de Pitágoras

Sumatoria de ángulos

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Usa la Ley de Cosenos

A

B

C

D

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Usa la Ley de Senos

A

B

C

D

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

¿Cuál es el valor del

ángulo que hace falta?

75°

90°

63°

73°

Tags

CCSS.8.G.A.5

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Indique cuál de las siguientes afirmaciones es verdadera con respecto al triángulo

Sen 55°13=SenC19\frac{Sen\ 55°}{13}=\frac{SenC}{19}

1913=SenBSen C\frac{19}{13}=\frac{SenB}{Sen\ C}

SenA13=SenC19\frac{SenA}{13}=\frac{SenC}{19}

19SenA=19SenB\frac{19}{SenA}=\frac{19}{SenB}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

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