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Changing the subject of a formula

Authored by Catherine Rivera

Mathematics

8th Grade

Used 52+ times

Changing the subject of a formula
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6 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Make b the subject of the formula  A=12(a+b)hA=\frac{1}{2}\left(a+b\right)h  .

 b=h2Aab=\frac{h}{2A}-a  

 b=2Ah+ab=\frac{2A}{h}+a  

 b=2Ahab=\frac{2A}{h}-a  

 b=h2A+ab=\frac{h}{2A}+a  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Make p the subject of the formula  d=p1+pd=\frac{p}{1+p}  .

 p=d1+dp=\frac{d}{1+d}  

 p=d1dp=\frac{d}{1-d}  

 p=1+ddp=\frac{1+d}{d}  

 p=1ddp=\frac{1-d}{d}  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Make R the subject of the formula  I=PRT100I=\frac{PRT}{100}  .

 R=100IPTR=\frac{100}{IPT}  

 R=100IPTR=\frac{100I}{PT}  

 R=IPT100R=\frac{IPT}{100}  

 R=PT100IR=\frac{PT}{100I}  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Make s the subject of the formula  v2=u2+2fsv^2=u^2+2fs  .

 s=v2+u22fs=\frac{v^2+u^2}{2f}  

 s=v2u22fs=\frac{v^2-u^2}{2f} 

 s=v2u22fs=\frac{v^2}{u^2-2f}  

 s=u2v2+2fs=\frac{u^2}{v_{ }^2+2f}  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Make l the subject of the formula t=2πlgt=2\pi\sqrt{\frac{l}{g}}  .

 l=Tg4π2l=\frac{Tg}{4\pi^2}  

 l=T2g42πl=\frac{T^2g}{4^2\pi}  

 l=T2g4π2l=\frac{T^2g}{4\pi^2}  

 l=T2g4πl=\frac{T^2g}{4\pi}  

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Make s the subject of the formula  t=u+u2+2gsgt=\frac{-u+\sqrt{u^2+2gs}}{g}  .

 s=t(gt+2u)2s=\frac{t\left(gt+2u\right)}{-2}  

 s=t(g+2u)2ts=\frac{t\left(g+2u\right)}{2t}  

 s=t(gt+2u)2s=\frac{t\left(gt+2u\right)}{2}  

 s=t(gt+2)2us=\frac{t\left(gt+2\right)}{2u}  

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