Completing the square for Circles

Complete the square for

x² - 12x + ____

• 144

• 36

• - 36

• 24

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Complete the square.

x² + 6x + ____

• 9

• 12

• 36

• - 9

Tags

CCSS.HSA-REI.B.4B

Given the perfect square trinomial, identify the equivalent expression

x²-18x+81

• (x-18)²

• (x-9)²

• (x+81)²

• (x+9)²

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25
• (x+3)² + (y-6)² = 25
• (x-3)² + (y+6)² = 45
• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form:
x² + y² + 4x + 6y - 36 = 0

• (x+2)² + (y+3)² = 49
• (x+2)² + (y+3)² = 13
• (x-2)² + (y-3)² = 49
• (x-2)² + (y-3)² = 13

Tags

CCSS.HSG.GPE.A.1

A circle has the equation  x² + y² - 12x + 8y + 3 = 0.  Use completing the square to write the equation in standard form.

• (x - 6)² + (y + 4)² = 49
• (x + 4)² + (y - 6)² = 49
• (x - 6)² + (y + 4)² = 55
• x² + y² = 55

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1

Find the center and radius of the circle: x²+y²+14x-2y=-1

• center= -7,2 radius= 3

• center= -7,1 radius= 7

• center= -4,1 radius= 5

Tags

CCSS.HSG.GPE.A.1

What does (h,k) standard for in the standard circle equation?

• (h,k) is the center of the circle

• (h,k) is a point on the circle.

• (h,k) is a point that we guess and find

• (h,k) is the distance of the circle

Tags

CCSS.HSG.GPE.A.1

What does the r in the standard equation stand for?

• r is the distance of the circle

• r is the radius of the circle

• r is the x coordinate of the center of the circle

• r is the y coordinate of the center of the circle

Tags

CCSS.HSG.GPE.A.1