graphing form of circles

What does (h,k) stand for in the standard circle equation?

• (h,k) is the center of the circle

• (h,k) is a point on the circle.

• (h,k) is a point that we guess and find

• (h,k) is the distance of the circle

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 2 and center (3, 4)?

• (x+3)² + (y+4)² = 2
• (x-3)² + (y-4)² = 2
• (x+3)² + (y+4)² = 4
• (x-3)² + (y-4)² = 4

Tags

CCSS.HSG.GPE.A.1

In order to convert from general form of a circle to graphing form, you must ___________.

• Multiply out

• expand

• factor

• complete the square

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x + 5)² + (y - 2)² = 144

• (x - 5)² + (y + 2)² = 36

• (x + 5)² + (y - 2)² = 36

• (x - 5)² + (y + 2)² = 12

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with equation x² + y² = 1?

• (1, 1)

• (0, 0)

• (0,1)

• not enough information

Tags

CCSS.HSG.GPE.A.1

Solve the equation.

x² + 13x + 40 = 0

• -8, 5

• -40, -1

• 5, 8

• -8, -5

Convert the to standard form. x² + y² + 6x - 10y - 15 = 0

• (x + 6)² + (y - 10)² = 225

• (x + 3)² + (y - 5)² = 361

• (x + 3)² + (y - 5)² = 7

• (x + 3)² + (y - 5)² = 49

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y+4)²=121, the radius of the circle is

• 242
• 11
• 121
• 22

Tags

CCSS.HSG.GPE.A.1

What is the center and radius given the equation, x² + y² + 8x - 2y - 64 = 0?

• Center: (-4, 1), Radius: 9

• Center: (4,1), Radius: 8

• Center: (1,-4), Radius: 64

• Center: (-4, 1), Radius: 81

Tags

CCSS.HSG.GPE.A.1

Solve the Quadratic Equation.

x² + 4x = 9

• -2 ± √13

• -2 ± 2√7

• -2 ± √7

• -2 + √7