Writing Exponential Functions

Quiz
•
Mathematics
•
9th Grade
•
Medium
+2
Standards-aligned
Kyndell [SCHS]
Used 838+ times
FREE Resource
17 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Which equation describes the story below?
You start with $5 and triple your money every day.
y=5(3)x
y=5x
y=5(3x)
y=15x
Tags
CCSS.HSF.LE.A.2
2.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Write an exponential function to model the situation. Then solve.
The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year. What will the cost be after 4 years?
C(t) = 12000(1.06)t ; $3149.72
C(t) = 12000(.06)t ; $3149.72
C(t) = 12000(.06)t ; $1472.95
C(t) = 12000(1.06)t ; $15149.72
Tags
CCSS.HSF.LE.A.2
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A particular type of cell triples in number every hour. Which function can be used to find the number of cells present at the end of h hours if there are initially 6 of these cells?
f(h) = 3(6)h
f(h) = 6xh
f(h) = 6(3)h
f(h) = 3(6h)
Tags
CCSS.HSF.LE.A.2
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
The amount of cola in a soda machine decreases by a rate of 5% each hour. The amount of cola in the machine was originally 75 gallons.
Which function models the amount of cola in gallons after h hours?
f(h) = 75(-5)h
f(h) = -5(75)h
f(h) = .95(75)h
f(h) = 75(.95)h
Tags
CCSS.HSF.LE.A.2
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
The function y = 24,220 (0.85)x represents Mr. Bittle's investment in the stock exchange where x is measured in months.
Which statement is NOT true.
Mr. Bittle loses 85% of his investment monthly
Mr. Bittle initially invested $24,220
Each month Mr. Bittle loses 15% of his investment
Tags
CCSS.HSF-IF.C.8B
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Write an exponential function to model the situation. You invest $1500. Your investment increases at a rate of 3.5%.
B(t) = 1500(0.965)t
B(t) = 1500(1.035)t
B(t) = 1500(.035)t
B(t) = 1500(1.965)t
Tags
CCSS.HSF.LE.A.2
7.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Write an exponential function to model the situation. The value of a car is $18000 and is depreciating at a rate of 12% per year.
V(t) = .88(18000)t
V(t) = .12(18000)t
V(t) = 18000(.88)t
V(t) = 18000(.12)t
Tags
CCSS.HSF.LE.A.2
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