Algebra exercises / Grade 9

An object costs 270LL. Its price is increased by 5%. The new price of the object is…

• 275 LL

• 283.5 LL

• 270.05 LL

 $3^{14}\ -3^{12}=$  

•  $3^2$  

•  $3^{12}\times8$  

• 6

n is a non-zero real number, 
 $\frac{n}{2}-\frac{n}{2}\times3=$  

• 3 

• 0

• -n

n is a natural number,
  $\left(\frac{4}{5}\right)^{n+1}\times\left(\frac{5}{4}\right)^n=$  

•  $8\times10^1$  

•  $1^{2n+1}$  

•  $8\times10^{\cdot1}$  

 $\frac{4}{5}-\frac{3}{5}\times\frac{10}{6}=$  

•  $-\frac{1}{5}$  

•  $\frac{26}{25}$  

•  $\frac{1}{3}$  

The natural numbers that are solutions of the following inequality 
 $4x-\frac{3}{2}\le\frac{5}{2}x+3\ are:$  

• 1 , 2 and 3

• 0 , 1 and 2

• 0 , 1 , 2 and 3

 The expanded form of the expression 
 $\left(2x+3\right)^2+\left(x-1\right)\left(2x+3\right)is:$  

•  $E=6x^2+13x+6$  

•  $E=6x^2+x+6$  

•  $E=6x^2+17x+6$  

The factorized form of the expression
 $E=\left(2x+3\right)^2+\left(x-1\right)\left(2x+3\right)\ is:$  

•  $\left(2x+3\right)\left(x\right)$  

•  $\left(2x+3\right)\left(3x+2\right)$  

•  $\left(2x+3\right)\left(3x+4\right)$  

 $P\left(x\right)=ax^2-4\left(x+5\right).\$  

 $If\ P\left(-2\right)=0.\ Then\ a=$  

• -3

• -6

• 3

 $If\ x=2\sqrt{2}+1\ then\ \frac{7}{x}=$  

•  $2\sqrt{2}-7$  

•  $2\sqrt{2}-1$  

•  $14\sqrt{2}-1$