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Rozklad na součin 2

Authored by Kateřina Dingová

Mathematics

8th - 10th Grade

Used 8+ times

Rozklad na součin 2
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10 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

2a(k-1)-3(1-k)=

(2a3)(k1)\left(2a-3\right)\left(k-1\right)

(2a+3)(1k)\left(2a+3\right)\left(1-k\right)

(2a+3)(k1)\left(2a+3\right)\left(k-1\right)

(2a3)(1k)\left(2a-3\right)\left(1-k\right)

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 4z2+8z+4z3=4z^2+8z+4z^3=  

 4z(z2+z+2)4z\left(z^2+z+2\right)  

 4z(z+4+z2)4z\left(z+4+z^2\right)  

 (2z+2)2\left(2z+2\right)^2  

 (z+4)2\left(z+4\right)^2  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 36mp18m6+12p=36mp-18m-6+12p=  

 (2p1)(18m+6)\left(2p-1\right)\left(18m+6\right)  

 (18m+6)(2p+1)\left(18m+6\right)\left(2p+1\right)  

 (18m+6)(12p)\left(18m+6\right)\left(1-2p\right)  

 (18m6)(12p)\left(18m-6\right)\left(1-2p\right)  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt


 25x29=25x^2-9=  

 (x3)(x+3)\left(x-3\right)\left(x+3\right)  

 (5x3)2\left(5x-3\right)^2  

 (5x+3)(5x3)\left(5x+3\right)\left(5x-3\right)   

 (25x3)(x+3)\left(25x-3\right)\left(x+3\right)  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Dvojčlen 16c2 – 169 lze rozložit na součin dvojčlenů:

(8c + 14) ∙ (8c – 14)

(4c – 13) ∙ (4c – 13)

(4c – 13) ∙ (4c + 13)

(4c – 14) ∙ (4c + 14)

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Vhodným vytknutím z výrazu x2 + 4xy + x4 získám součin:

x ∙(x + 4y + x2)

x ∙(x + 4y2 + x2)

x ∙(x + 4y + x3)

x ∙(4y + x3)

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

  (a2)225 =(a-2)^2-25\ =  

 (a7)(a+7)\left(a-7\right)\left(a+7\right)  

 (a7)(a+3)\left(a-7\right)\left(a+3\right)  

 a24a21a^2-4a-21  

jinak

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