Calculus 1

Calculus 1

12th Grade

20 Qs

quiz-placeholder

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Calculus 1

Calculus 1

Assessment

Quiz

Mathematics

12th Grade

Hard

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The Sheldonator

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20 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Differentiate  y=e7xy=e^{7x}  .

 dydx=e7x\frac{\text{d}y}{\text{d}x}=e^{7x}  

 dydx=7ex\frac{dy}{\text{d}x}=7e^x  

 dydx=17ex\frac{\text{d}y}{\text{d}x}=\frac{1}{7}e^x  

 dydx=7e7x\frac{\text{d}y}{\text{d}x}=7e^{7x}  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Differentiate  f(x)=x3(x7)(2x+1)f\left(x\right)=x^3\left(x-7\right)\left(2x+1\right)  

 f(x)=3x2(2x211x21)x3(4x11)f'\left(x\right)=3x^2\left(2x^2-11x-21\right)-x^3\left(4x-11\right)  

 f(x)=3x2(x7)(2x+3)+x3(2x+3)+x3(x7)f'\left(x\right)=3x^2\left(x-7\right)\left(2x+3\right)+x^3\left(2x+3\right)+x^3\left(x-7\right)  

 f(x)=10x444x363x2f'\left(x\right)=10x^4-44x^3-63x^2  

 f(x)=3x2(x7)(2x+3)+x3(4x7)f'\left(x\right)=3x^2\left(x-7\right)\left(2x+3\right)+x^3\left(4x-7\right)  

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 limx7 x7x32\lim_{x\rightarrow7}\ \frac{x-7}{\sqrt{x-3}-2}  

0

4

Does not exist.

 47\frac{4}{7}  

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Differentiate  y=42x3y=4^{2x-3}  

 y=2ln442x3y'=2\ln4\cdot4^{2x-3}  

 y=(2x3)ln442x3y'=\left(2x-3\right)\ln4\cdot4^{2x-3}  

 y=ln442x3y'=\ln4\cdot4^{2x-3}  

 y=ln842x3y'=\ln8\cdot4^{2x-3}  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Differentiate  y=ex2sinx3y=e^{x^2\sin x^3}  

 dydx=ex2sinx3(2xcosx3)\frac{\text{d}y}{\text{d}x}=e^{x^2\sin x^3}\cdot\left(2x\cos x^3\right)  

 dydx=ex2sinx3\frac{\text{d}y}{\text{d}x}=e^{x^2\sin x^3}  

 dydx=ex(5x4cosx3)\frac{\text{d}y}{\text{d}x}=e^x\cdot\left(5x^4\cos x^3\right)  

 dydx=ex2sinx3(2xsinx3+3x4cosx3)\frac{\text{d}y}{\text{d}x}=e^{x^2\sin x^3}\cdot\left(2x\sin x^3+3x^4\cos x^3\right)  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 limx1 x131x1\lim_{x\rightarrow1}\ \frac{x^{\frac{1}{3}}-1}{x-1}  

 13\frac{1}{3}  

 14\frac{1}{4}  

 33  

Does not exist.

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the initial acceleration of a particle whose position is given by  s(t)=e5t+sints\left(t\right)=-e^{5t}+\sin t  , where  ss  is the distance traveled in metres,  tt  seconds after it starts moving.

 e5 ms2-e^5\ \frac{m}{s^2}  

 25 ms2-25\ \frac{m}{s^2}  

 5e5+1 ms2-5e^5+1\ \frac{m}{s^2}  

 0 ms20\ \frac{m}{s^2}  

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