SN5-Mod08-FctTrigo01

SN5-Mod08-FctTrigo01

9th - 11th Grade

20 Qs

quiz-placeholder

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SN5-Mod08-FctTrigo01

SN5-Mod08-FctTrigo01

Assessment

Quiz

Mathematics

9th - 11th Grade

Practice Problem

Easy

Created by

Patrice Audet

Used 17+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Quelle est la période de 

f(x) =   5 sin 3(x +π4)  4-5\ \sin\ 3\left(x\ +\frac{\pi}{4}\right)\ -\ 4  

 π3\frac{\pi}{3}  

 2π3\frac{2\pi}{3}  

 2π5\frac{2\pi}{5}  

 π4\frac{\pi}{4}  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Quelle est l'amplitude de la fonction 
f(x) =  5 sin 3(x +π4)  4-5\ \sin\ 3\left(x\ +\frac{\pi}{4}\right)\ -\ 4   

5

3

4

 π4\frac{\pi}{4}  

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Soit f(x) = 3 sin (x π2)  4-3\ \sin\ \left(x\ -\frac{\pi}{2}\right)\ -\ 4  
Que vaut f(0) ?

7

-7

1

-1

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Laquelle des fonctions sinusoïdales suivantes a un maximum de 2 ?

 f(x) =sin(3(xπ3)) + 3f\left(x\right)\ =-\sin\left(3\left(x-\frac{\pi}{3}\right)\right)\ +\ 3  

 f(x) =5sin(3(xπ3)) + 3f\left(x\right)\ =5\sin\left(3\left(x-\frac{\pi}{3}\right)\right)\ +\ 3  

 f(x) =sin(3(xπ3))  3f\left(x\right)\ =-\sin\left(3\left(x-\frac{\pi}{3}\right)\right)\ -\ 3  

 f(x) =5sin(3(xπ3))  3f\left(x\right)\ =5\sin\left(3\left(x-\frac{\pi}{3}\right)\right)\ -\ 3  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Quelle est la règle de la fonction ci-dessus ? (Le point d'inflexion A est donné)

f(x) = 2 sin 12(x + π3) + 1f\left(x\right)\ =\ 2\ \sin\ \frac{1}{2}\left(x\ +\ \frac{\pi}{3}\right)\ +\ 1

f(x) = 2 sin 2(x π3) + 1f\left(x\right)\ =\ 2\ \sin\ 2\left(x\ -\ \frac{\pi}{3}\right)\ +\ 1

f(x) = 2 sin 12(x π3) + 1f\left(x\right)\ =\ 2\ \sin\ \frac{1}{2}\left(x\ -\ \frac{\pi}{3}\right)\ +\ 1

f(x) = 2 sin 2(x + π3) + 1f\left(x\right)\ =\ 2\ \sin\ 2\left(x\ +\ \frac{\pi}{3}\right)\ +\ 1

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Quelle est la règle de la fonction sinus ci-dessus (le point d'inflexion A est donné)

 f(x)=3 sin 2(x + π4)2f\left(x\right)=3\ \sin\ 2\left(x\ +\ \frac{\pi}{4}\right)-2  

 f(x)=3 sin 2(x + π4)2f\left(x\right)=-3\ \sin\ 2\left(x\ +\ \frac{\pi}{4}\right)-2  

 f(x)=3 sin 2(x  π4)2f\left(x\right)=-3\ \sin\ 2\left(x\ -\ \frac{\pi}{4}\right)-2  

 f(x)=3 sin 2(x  π4)2f\left(x\right)=3\ \sin\ 2\left(x\ -\ \frac{\pi}{4}\right)-2  

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Quelle est la règle de la fonction ci-dessus (le point d'inflexion A est illustré)

f(x)=4sin(π6(x+5))2f\left(x\right)=4\sin\left(\frac{\pi}{6}\left(x+5\right)\right)-2

f(x)=4sin(π6(x+5))2f\left(x\right)=-4\sin\left(\frac{\pi}{6}\left(x+5\right)\right)-2

f(x)=4sin(π6(x5))2f\left(x\right)=4\sin\left(\frac{\pi}{6}\left(x-5\right)\right)-2

f(x)=4sin(π6(x5))2f\left(x\right)=-4\sin\left(\frac{\pi}{6}\left(x-5\right)\right)-2

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