Parallel & Perpendicular Lines through a given point

Parallel & Perpendicular Lines through a given point

8th - 10th Grade

10 Qs

quiz-placeholder

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Parallel & Perpendicular Lines through a given point

Parallel & Perpendicular Lines through a given point

Assessment

Quiz

Mathematics

8th - 10th Grade

Practice Problem

Hard

CCSS
HSG.GPE.B.5, 4.G.A.1, HSG.GPE.A.1

+3

Standards-aligned

Created by

Aida Bernal

Used 145+ times

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10 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

Which of the following equations are parallel to y=7x+4? (Check all that apply)

y=7x+17

y=-7x-5

y=17x+5y=\frac{1}{7}x+5

y=17x3y=-\frac{1}{7}x-3

y-1=7(x+5)

Tags

CCSS.4.G.A.1

CCSS.HSG.CO.A.1

2.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

Which of the following equations are perpendicular to y=-4x-2? (Check all that apply)

y=14x+9y=-\frac{1}{4}x+9

y+2=-4(x+11)

y=14x+17y=\frac{1}{4}x+17

y10=14(x2)y-10=\frac{1}{4}\left(x-2\right)

y=4x+10

Tags

CCSS.4.G.A.1

CCSS.HSG.CO.A.1

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Determine the equation of a line perpendicular to   y=15x+8y=-\frac{1}{5}x+8 and going through the point (5, 10), in slope-intercept form.

y=5x+35

y=5x-15

y=-5x-35

y=-5x+15

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.B.5

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Determine the equation of a line perpendicular to y=-3x-2 and going through the point (9, 2), in slope-intercept form.

y=13x3y=\frac{1}{3}x-3

y=13x9y=-\frac{1}{3}x-9

y=13x1y=\frac{1}{3}x-1

y=3x9y=-3x-9

Tags

CCSS.HSG.GPE.B.5

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Which of the following shows an equation of a line parallel to  y=3x+72y=3x+\frac{7}{2}  and going through point (-4, -5), in slope-intercept form?

y=3x+7

y=-3x-7

y=3x-17

y=-3x+17

y=3x-7

Tags

CCSS.HSG.GPE.B.5

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Determine the equation of a line perpendicular to  (y2)=34(x+10)\left(y-2\right)=-\frac{3}{4}\left(x+10\right)  and goes through the point (4, -2), in point-slope form?

 y+2=43(x4)y+2=\frac{4}{3}\left(x-4\right)  

 y2=43(x+4)y-2=\frac{4}{3}\left(x+4\right)  

 y+2=43(x4)y+2=-\frac{4}{3}\left(x-4\right)  

 y2=34(x+4)y-2=-\frac{3}{4}\left(x+4\right)  

 y+2=34(x4)y+2=-\frac{3}{4}\left(x-4\right)  

Tags

CCSS.HSG.GPE.A.1

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Determine the equation of a line perpendicular to 
 (y+5)=37(x+12)\left(y+5\right)=\frac{3}{7}\left(x+12\right)  and goes through the point (-4, 8), in point-slope form?

 y+4=73(x+8)y+4=-\frac{7}{3}\left(x+8\right)  

 y+4=73(x8)y+4=-\frac{7}{3}\left(x-8\right)  

 y+8=73(x4)y+8=-\frac{7}{3}\left(x-4\right)  

 y8=37(x4)y-8=-\frac{3}{7}\left(x-4\right)  

 y8=73(x+4)y-8=-\frac{7}{3}\left(x+4\right)  

Tags

CCSS.HSG.GPE.A.1

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