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Pythagorean Theorem and Trig Ratios

Authored by Pamela Smith

Mathematics

9th - 12th Grade

CCSS covered

Used 14K+ times

Pythagorean Theorem and Trig Ratios
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14 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

For the above right triangle, find the side length x.

16

41

29

25

Tags

CCSS.8.G.B.7

2.

FILL IN THE BLANK QUESTION

5 mins • 12 pts

Media Image

The length of a shadow of a building is 29m. The distance from the top of the building to the tip of the shadow is 36m. The height of the building is ____m. If necessary, round your answer to the nearest tenth.

Tags

CCSS.8.G.B.7

3.

MULTIPLE CHOICE QUESTION

3 mins • 12 pts

Media Image

For the above right triangle, find the side length of x. Round your answer to the nearest hundredth.

13.04

8.49

72.00

10.23

Tags

CCSS.8.G.B.7

4.

MULTIPLE SELECT QUESTION

3 mins • 1 pt

Determine whether a triangle with the given side lengths is a right triangle.

Check all correct answers.

14, 48, 50

8, 14, 16

10, 11,15

5,12,13

Tags

CCSS.8.G.B.8

5.

MULTIPLE CHOICE QUESTION

2 mins • 12 pts

Media Image

Use the above triangle to find  cosB\cos B  ,  tanB\tan B  , and  sinB\sin B  

 cosB=1517, tanB=158, sinB=817\cos B=\frac{15}{17},\ \tan B=\frac{15}{8},\ \sin B=\frac{8}{17}  

 cosB=817, tanB=158, sinB=1517\cos B=\frac{8}{17},\ \tan B=\frac{15}{8},\ \sin B=\frac{15}{17}  

 cosB=1517, tanB=815, sinB=817\cos B=\frac{15}{17},\ \tan B=\frac{8}{15},\ \sin B=\frac{8}{17}  

 cosB=815, tanB=817, sinB=1517\cos B=\frac{8}{15},\ \tan B=\frac{8}{17},\ \sin B=\frac{15}{17}  

Tags

CCSS.HSG.SRT.C.6

6.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Media Image

Use the above right triangle, with side lengths a, b, and c. The sinx = ______.

bc\frac{b}{c}

cb\frac{c}{b}

ac\frac{a}{c}

ca\frac{c}{a}

Tags

CCSS.HSG.SRT.C.6

7.

MULTIPLE CHOICE QUESTION

2 mins • 12 pts

Media Image

Find cosθ\cos\theta , where  θ\theta  is the angle shown.  Give an exact value, not a decimal approximation.

 75\frac{7}{5}  

 57\frac{5}{7}  

 257\frac{25}{7}  

 725\frac{7}{25}  

Tags

CCSS.HSG.SRT.C.6

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