Quiz Volume: Disc Method

Determine the region that is bounded by  $y=4-x^2$  , y=0, x=0 , in Quadrant I.  

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Tags

CCSS.HSA.REI.D.12

Find the RADIUS of the region that is bounded by  $y=4-x^2$  , y=0, x=0 , in Quadrant I and rotated about the x-axis. 

•  $4-x^2$  

•  $\left(4-x^2\right)^2$  

• 4

• x

Find the "a" and "b" of the region that is bounded by  $y=4-x^2$  , y=0, x=0 , in Quadrant I and rotated about the x-axis. (left and right bounds)

• a=0, b=0

• a=-2, b=0

• a=0, b=2

• a=-2, b=2

Determine the integral that represents the volume of the region that is bounded by  $y=4-x^2$  , y=0, x=0 , in Quadrant I and rotated about the x-axis. 

•  $\pi\int_0^2\left(4-x^2\right)dx$  

•  $\pi\int_0^{100}\left(4-x^2\right)^2dx$  

•  $\int_0^2\left(4-x^2\right)^2dx$  

•  $\pi\int_0^2\left(4-x^2\right)^2dx$  

Determine the volume of the region that is bounded by  $y=4-x^2$  , y=0, x=0 , in Quadrant I and rotated about the x-axis. 

•  $\frac{256}{15}\pi$  

•  $\frac{256}{15}$  

•  $\frac{16}{3}\pi$  

•  $\frac{16}{3}$  

Determine the region that is bounded by  $y=\sqrt{9-x^2}$  and y=0.

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Find the RADIUS of the region that is bounded by  $y=\sqrt{9-x^2}$  and y=0 and rotated about the x-axis. 

•  $9-x^2$  

•  $\left(\sqrt{9-x^2}\right)^2$  

•  $\sqrt{9-x^2}$  

•  $x^2$  

Find the "a" and "b" of the region that is bounded by  $y=\sqrt{9-x^2}$  and y=0 , rotated about the x-axis. (left and right bounds)

• a=0, b=0

• a=-3, b=0

• a=0, b=3

• a=-3, b=3

Determine the integral that represents the volume of the region that is bounded by  $y=\sqrt{9-x^2}$  and y=0 , and rotated about the x-axis. 

•  $\pi\int_0^3\left(9-x^2\right)^2dx$  

•  $\pi\int_0^{300}\left(\sqrt{9-x^2}\right)^2dx$  

•  $\int_{-3}^3\left(\sqrt{9-x^2}\right)^2dx$  

•  $\pi\int_{-3}^3\left(\sqrt{9-x^2}\right)^2dx$  

Determine the volume of the region that is bounded by  $y=\sqrt{9-x^2}$  and y=0 , and rotated about the x-axis. 

•  $36\pi$  

• 36

•  $18\pi$  

• 18