Lingkaran

Lingkaran

11th Grade

10 Qs

quiz-placeholder

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Lingkaran

Lingkaran

Assessment

Quiz

Mathematics

11th Grade

Medium

Created by

Ivone Amelia

Used 41+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jari - jari lingkaran dengan persamaan 3x2 + 3y2 - 4x + 6y - 12 = 0 adalah R. Maka R + 2 = ...

3123\frac{1}{2}

413 4\frac{1}{3\ }

5235\frac{2}{3}

7137\frac{1}{3}

9139\frac{1}{3}

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran yang mempunyai diameter AB dimana A ( 3,5 ) dan B ( -5, 9 ) adalah ... 

 x2+y2+2x14y+30=0x^2+y^2+2x-14y+30=0  

 x2+y2+2x+4y30=0x^2+y^2+2x+4y-30=0  

 x2+y22x14y+4=0x^2+y^2-2x-14y+4=0  

 x2+y2+2x14y30=0x^2+y^2+2x-14y-30=0  

 x2+y2+2x14y4=0x^2+y^2+2x-14y-4=0  

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Persamaan lingkaran yang berpusat di ( 1, - 2 ) dan menyinggung 6y - 8x - 10 = 0 

 x2+y22x+4y4=0x^2+y^2-2x+4y-4=0  

 x2+y26x8y+9=0x^2+y^2-6x-8y+9=0  

 x2+y22x+4y9=0x^2+y^2-2x+4y-9=0  

 x2+y22x+4y+4=0x^2+y^2-2x+4y+4=0  

 x2+y26x8y9=0x^2+y^2-6x-8y-9=0  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Batas nilai a jika titik ( a, a ) terletak di luar lingkaran  x2+y2+2x2y2=0x^2+y^2+2x-2y-2=0  adalah ...

 a<1a<-1  

 a>1a>1  

 1<a<1-1<a<1  

 a<1 atau a>1a<-1\ atau\ a>1  

 a=1 atau a = 1a=-1\ atau\ a\ =\ 1  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Salah satu titik potong garis  yx2=0y-x-2=0  terhadap lingkaran  x2+y26x+4y12=0x^2+y^2-6x+4y-12=0  adalah ...

 (1,0)\left(-1,0\right)  

 (0,1)\left(0,1\right)  

 (1,1)\left(-1,1\right)  

 (2,0)\left(2,0\right)  

 (2,1)\left(2,1\right)  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diberikan dua lingkaran dengan persamaan    L1x2+y22x8y+9=0L_1\equiv x^2+y^2-2x-8y+9=0 
 L2x2+y22x4y+1=0L_2\equiv x^2+y^2-2x-4y+1=0  

Koordinat titik potong kedua lingkaran adalah ...

 (3,2)\left(-3,2\right)  

 (2,2)\left(-2,2\right)  

 (1,2)\left(-1,2\right)  

 (0,2)\left(0,2\right)  

 (1,2)\left(1,2\right)  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Salah satu persamaan garis singgung pada lingkaran  (x+2)2+(y1)2=9\left(x+2\right)^2+\left(y-1\right)^2=9 dan tegak lurus garis  4x3y+12=04x-3y+12=0   adalah ...

 3x4y13=03x-4y-13=0  

 3x+4y13=03x+4y-13=0  

 3x4y+17=03x-4y+17=0  

 4x+3y15=04x+3y-15=0  

 4x+3y+13=04x+3y+13=0  

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