acidi, basi  e pH

acidi, basi e pH

12th Grade

10 Qs

quiz-placeholder

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acidi, basi  e pH

acidi, basi e pH

Assessment

Quiz

Chemistry

12th Grade

Practice Problem

Hard

Created by

Alfredo Tifi

Used 109+ times

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10 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

10 sec • 1 pt

Come si chiama la specie acida più abbondante nelle soluzioni acquose acide?

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Una soluzione ha [H3O+] = 0,0002\left[H_3O^+\right]\ =\ 0,0002  . Il suo pH è compreso tra

3,0 e 4,0

4,0 e 4,2

2 e 3

4 e 5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Se una soluzione ha pH 5, la concentrazione degli ioni idrossido sarà...

10910^{-9}

10+910^{+9}

10+510^{+5}

10510^{-5}

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Quale soluzione è di un acido debole?  ( Ca C_a\   è la concentrazione dell'acido debole)

Ca = 0,01 M; pH = 2C_a\ =\ 0,01\ M;\ pH\ =\ 2

Ca = 0,001 M; pH = 3C_a\ =\ 0,001\ M;\ pH\ =\ 3

Ca = 0,01 M; pH = 3C_a\ =\ 0,01\ M;\ pH\ =\ 3

Ca = 1,0104 M; pH = 4C_a\ =\ 1,0\cdot10^{-4}\ M;\ pH\ =\ 4

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Quale soluzione acquosa non può esistere a 25 °C?

pH = 8; [OH] = 1,0108pH\ =\ 8;\ \left[OH^-\right]\ =\ 1,0\cdot10^{-8}

[H3O+] = 108; [OH] = 1,0106\left[H_3O^+\right]\ =\ 10^{-8};\ \left[OH^-\right]\ =\ 1,0\cdot10^{-6}

pH = 6; [OH] = 1,0108pH\ =\ 6;\ \left[OH^-\right]\ =\ 1,0\cdot10^{-8}

[H3O+] = 1012; [OH] = 0,01\left[H_3O^+\right]\ =\ 10^{-12};\ \left[OH^-\right]\ =\ 0,01

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Quale equazione di reazione è più prossima ad essere completa?

2H2O H3O+ + OH2H_2O\ \longrightarrow\ H_3O^+\ +\ OH^-

OH + H3O+ 2H2OOH^{-\ }+\ H_3O^+\ \rightarrow\ 2H_2O

Cl + H3O+ HCl + H2OCl^-\ +\ H_3O^+\ \rightarrow\ HCl\ +\ H_2O

CH3COOH + H2O CH3COO + H3O+CH_3COOH\ +\ H_2O\ \rightarrow\ CH_3COO^-\ +\ H_3O^+

7.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Spunta le due soluzioni neutre

[H+] = 5106; [OH] = 5106\left[H^+\right]\ =\ 5\cdot10^{-6};\ \left[OH^-\right]\ =\ 5\cdot10^{-6}

[H+] = 1,0107; [OH] = 10108\left[H^+\right]\ =\ 1,0\cdot10^{-7};\ \left[OH^-\right]\ =\ 10\cdot10^{-8}

[H+] = 2107; [OH] = 5108\left[H^+\right]\ =\ 2\cdot10^{-7};\ \left[OH^-\right]\ =\ 5\cdot10^{-8}

[H+] = 106,5; [OH] = 107,5\left[H^+\right]\ =\ 10^{-6,5};\ \left[OH^-\right]\ =\ 10^{-7,5}

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