Sect. 5.1 Finding Zeros using Rational Root Theorem

Which of the following is a COMPLETE  list of all possible Rational Zeros?
f(x) = x³ + 2x² - 6x + 8

• ±1, ±8
• ±1, ±2, ±4, ±8
• ±1, ±2, ±4
• 1, 2, 4, 8

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Solve by using Rational Root Theorem: 
2x³ - 11x² + 12x + 9 = 0

• -1, 1, 3
• -1, 3/2, 3 
• -1/2, 3, 3
• -1/2, 1, 3

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Solve by using Rational Root Theorem: 
x³ - 7x - 6 = 0

• 1, 2, 3
• -1, -2, - 3
• -1, -2, 3
• 1,-2,-3

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

According to the Rational Root Theorem, what are the all possible rational roots? 
2x³ - 11x² + 12x + 9 = 0

• ±1,±2
• ±1,±3,±9
• ±1,±3±9,±1/2,±3/2,±9/2
• ±1,±2,±1/3,±2/3,±1/9,±2/9

Tags

CCSS.HSA.APR.B.3

Solve by using Rational Root Theorem: 
x³ + 3x² - 6x - 8 = 0

•  -4, -1, 2
• -4, -1, ±√2
• 1, 2, 4
• 4,-1,√2

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Below are four possible zeros for this polynomial.

Figure out which one "works"

f(x) = x³ + 2x² - 11x - 12

• -3

• -4

• 1

• 6

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

What are the zeros (x-intercepts)?

• x = 4, 7
• x = -1, 4/7
• x = -4/7, 1
• x = 7, -4

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Find all real solutions of the polynomial equation x³ - 3x² - 2x + 4 = 0

• x = -1, 1 ± √5
• x = 1, 1 + √5
• x = 2, 1 ± √5
• x = 1, 1 ± √5

Tags

CCSS.HSA.APR.B.3

One zero of 2x³-13x²+36 is 2.
What is another zero?

• 3/2
• 6
• 2
• -6

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Find all real solutions of the polynomial equation x³-3x²+2=0

• x = 1, - 1 ± √3
• x= -1, 1 ± √3
• x= 1 ± √3, -1
• x=1, 1 ± √3

Tags

CCSS.HSA.APR.B.3