Find the remaining trig ratios if sin ⁡ θ = 2 3 \sin\theta=\frac{2}{3} sin θ = 3 2

cos ⁡ θ = 5 3 tan ⁡ θ = 2 5 5 csc ⁡ θ = 3 2 sec ⁡ θ = 3 5 5 cot ⁡ θ = 5 2 \cos\theta=\frac{\sqrt{5}}{3}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{3\sqrt{5}}{5}\cot\theta=\frac{\sqrt{5}}{2} cos θ = 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> tan θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> csc θ = 2 3 sec θ = 5 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cot θ = 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ θ = 5 7 tan ⁡ θ = 2 5 \cos\theta=\frac{5}{7}\ \tan\theta=\frac{2}{5} cos θ = 7 5 tan θ = 5 2 csc ⁡ θ = 3 2 sec ⁡ θ = 7 5 cot ⁡ θ = 5 2 \csc\theta=\frac{3}{2}\ \sec\theta=\frac{7}{5}\ \cot\theta=\frac{5}{2} csc θ = 2 3 sec θ = 5 7 cot θ = 2 5

cos ⁡ θ = 2 5 5 tan ⁡ θ = 2 3 \cos\theta=\frac{2\sqrt{5}}{5}\ \tan\theta=\frac{2}{3} cos θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> tan θ = 3 2 csc ⁡ θ = 3 2 sec ⁡ θ = 5 2 cot ⁡ θ = 3 2 \csc\theta=\frac{3}{2}\ \sec\theta=\frac{\sqrt{5}}{2}\ \cot\theta=\frac{3}{2} csc θ = 2 3 sec θ = 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cot θ = 2 3

cos ⁡ θ = 5 2 tan ⁡ θ = 2 5 5 csc ⁡ θ = 3 2 sec ⁡ θ = 2 5 5 cot ⁡ θ = 5 5 2 \cos\theta=\frac{\sqrt{5}}{2}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{2\sqrt{5}}{5}\cot\theta=\frac{5\sqrt{5}}{2} cos θ = 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> tan θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> csc θ = 2 3 sec θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cot θ = 2 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Reciprocal Trig Functions and Applying Trig Functions

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Reciprocal Trig Functions and Applying Trig Functions

Quiz

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Mathematics

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9th Grade - University

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Practice Problem

•

Medium

•

CCSS

HSG.SRT.C.8, HSG.SRT.C.6, HSF.TF.A.2

Standards-aligned

Kelsey Johnson

Used 57+ times

FREE Resource

10 questions

Show all answers

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Write all six trig ratios.

$\sin\theta=\frac{24}{25}\ \cos\theta=\frac{7}{25}\ \tan\theta=\frac{24}{7}\$ $\csc\theta=\frac{25}{24}\ \sec\theta=\frac{25}{7}\ \cot\theta=\frac{7}{24}$

$\sin\theta=\frac{7}{25}\ \cos\theta=\frac{24}{25}\ \tan\theta=\frac{7}{24}$ $\csc\theta=\frac{25}{7}\ \sec\theta=\frac{25}{24}\ \cot\theta=\frac{24}{7}$

Tags

CCSS.HSF.TF.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

$\cos\theta=\frac{5}{7}\ \tan\theta=\frac{2}{5}$ $\csc\theta=\frac{3}{2}\ \sec\theta=\frac{7}{5}\ \cot\theta=\frac{5}{2}$

$\cos\theta=\frac{2\sqrt{5}}{5}\ \tan\theta=\frac{2}{3}$ $\csc\theta=\frac{3}{2}\ \sec\theta=\frac{\sqrt{5}}{2}\ \cot\theta=\frac{3}{2}$

$\cos\theta=\frac{\sqrt{5}}{2}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{2\sqrt{5}}{5}\cot\theta=\frac{5\sqrt{5}}{2}$

$\cos\theta=\frac{\sqrt{5}}{3}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{3\sqrt{5}}{5}\cot\theta=\frac{\sqrt{5}}{2}$

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing side. Round answers to the nearest tenth.

39.4

12.2

29.1

Tags

CCSS.HSG.SRT.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing side. Round answers to the nearest tenth.

2.6

6.7

13.7

5.4

Tags

CCSS.HSG.SRT.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing angle. Round answers to the nearest whole degree.

$50\degree$

$40\degree$

$1\degree$

$33\degree$

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing angle. Round answers to the nearest whole degree.

$64\degree$

$35\degree$

$51\degree$

$63\degree$

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the reciprocal function to sin?

sec

cos

csc

cot

Tags

CCSS.HSF.TF.A.2

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Reciprocal Trig Functions and Applying Trig Functions

10 questions

Write all six trig ratios.

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

Find the missing side. Round answers to the nearest tenth.

Find the missing side. Round answers to the nearest tenth.

Find the missing angle. Round answers to the nearest whole degree.

Find the missing angle. Round answers to the nearest whole degree.

What is the reciprocal function to sin?

What is the reciprocal function of sec?

What is the reciprocal function of tan?

If $\sec\theta=\frac{29}{20}$ , then what is the hypotenuse?

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Reciprocal Trig Functions and Applying Trig Functions

10 questions

Write all six trig ratios.

Find the remaining trig ratios if sin⁡θ=23\sin\theta=\frac{2}{3}sinθ=32​

Find the missing side. Round answers to the nearest tenth.

Find the missing side. Round answers to the nearest tenth.

Find the missing angle. Round answers to the nearest whole degree.

Find the missing angle. Round answers to the nearest whole degree.

What is the reciprocal function to sin?

What is the reciprocal function of sec?

What is the reciprocal function of tan?

If sec⁡θ=2920\sec\theta=\frac{29}{20}secθ=2029​ , then what is the hypotenuse?

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Discover more resources for Mathematics

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

If $\sec\theta=\frac{29}{20}$ , then what is the hypotenuse?