PHUONG TRINH MAT CAU

PHUONG TRINH MAT CAU

12th Grade

20 Qs

quiz-placeholder

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PHUONG TRINH MAT CAU

PHUONG TRINH MAT CAU

Assessment

Quiz

Mathematics

12th Grade

Practice Problem

Hard

CCSS
HSG.GPE.A.1, 8.G.C.9, HSG.GMD.A.3

Standards-aligned

Created by

Trong van

Used 58+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Phương trình nào sau đây là pt mặt cầu

x2+y2+z22x=0x^2+y^2+z^2-2x=0

x2+y2z22x+y+1=0x^2+y^2-z^2-2x+y+1=0

2x2+2y2+z22xy=02x^2+2y^2+z^2-2xy=0

x2+y2+z22xy2yz2zx=0x^2+y^2+z^2-2xy-2yz-2zx=0

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Mặt cầu  
 (x1)2+(y+2)2+z2=9\left(x-1\right)^2+\left(y+2\right)^2+z^2=9  có tâm là:

 I(1;2;0)I\left(1;-2;0\right)  

 I(1;2;0)I\left(-1;2;0\right)  

 I(1;2;0)I\left(1;2;0\right)  

 I(1;2;1)I\left(-1;2;1\right)  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Mặt cầu (S):  x2+y2+z28x+2y+1=0x^2+y^2+z^2-8x+2y+1=0  có tâm là:

 I(8;2;0)I\left(8;-2;0\right)  

 I(4;1;0)I\left(-4;1;0\right)  

 I(8;2;1)I\left(-8;2;1\right)  

 I(4;1;0)I\left(4;-1;0\right)  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Mặt cầu (S): x2+y2+z24x+1=0x^2+y^2+z^2-4x+1=0  có tâm và bán kính là:

 I(2;0;0), R=3I\left(2;0;0\right),\ R=\sqrt{3}  

 I(2;0;0), R=3I\left(2;0;0\right),\ R=3  

 I(0;2;0), R=3I\left(0;2;0\right),\ R=\sqrt{3}  

 I(2;0;0), R=3I\left(-2;0;0\right),\ R=\sqrt{3}  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Phương trình mặt cầu (S) có tâm I(1;2;3), baˊn kıˊnh R=3I\left(-1;2;-3\right),\ bán\ kính\ R=3  là:

 (S): (x+1)2+(y2)2+(z+3)2=9\left(S\right):\ \left(x+1\right)^2+\left(y-2\right)^2+\left(z+3\right)^2=9  

 (S): (x1)2+(y+2)2+(z3)2=9\left(S\right):\ \left(x-1\right)^2+\left(y+2\right)^2+\left(z-3\right)^2=9  

 (S): (x+1)2+(y2)2+(z3)2=3\left(S\right):\ \left(x+1\right)^2+\left(y-2\right)^2+\left(z-3\right)^2=3  

 (S): (x1)2+(y+2)2+(z+3)2=32\left(S\right):\ \left(x-1\right)^2+\left(y+2\right)^2+\left(z+3\right)^2=3^2  

Tags

CCSS.HSG.GPE.A.1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Mặt cầu (S): 3x2+3y2+3z26x+12y+2=03x^2+3y^2+3z^2-6x+12y+2=0  có bán kính là: 

 133\sqrt{\frac{13}{3}}  

 213\frac{\sqrt{21}}{3}  

 273\frac{2\sqrt{7}}{3}  

 73\frac{\sqrt{7}}{3}  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Đường kính của mặt cầu (S):  (x+1)2+(y2)2+z2=4\left(x+1\right)^2+\left(y-2\right)^2+z^2=4  là:

2

4

8

16

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