Combination / Gabungan SPM
Quiz
•
Mathematics
•
9th - 10th Grade
•
Medium
WONG Moe
Used 11+ times
FREE Resource
8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A badminton team consist of 7 students. The team will be chosen from a group of 8 boys and 5 girls.
Find the number of team that can be formed such that each team consists of 4 boys.
Satu pasukan badminton terdiri daripada 7 orang pelajar. Pasukan itu akan dipilih daripada sekumpulan 8 pelajar lelaki dan 5 pelajar perempuan.
Carikan bilangan pasukan yang boleh dibentuk supaya setiap pasukan itu mempunyai 4 pelajar lelaki.
8C4 X 5C2
8C4 X 5C3
7C4 X 5C2
7C4 X 5C3
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A badminton team consist of 7 students. The team will be chosen from a group of 8 boys and 5 girls.
Find the number of team that can be formed such that each team consists of not more than 2 girls.
Satu pasukan badminton terdiri daripada 7 orang pelajar. Pasukan itu akan dipilih daripada sekumpulan 8 pelajar lelaki dan 5 pelajar perempuan. Carikan bilangan pasukan yang boleh dibentuk supaya setiap pasukan itu mempunyai tidak lebih daripada 2 pelajar perempuan.
8C7+8C6X5C1+8C5X5C2+8C4X5C3
8C7+8C6X5C1+8C5X5C2
8C7+8C6X5C1
8C7
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A debating team consists of 5 students. These 5 students are chosen from 4 monitors, 2 assistant monitors and 6 prefects.
Calculate the number of different ways the team can be formed if there is no restriction.
Satu pasukan bahas terdiri daripada 5 orang pelajar. Pasukan 5 orang pelajar itu dipilih daripada 4 ketua darjah, 2 orang penolong ketua darjah dan 6 orang pengawas.
Hitungkan bilangan cara yang berlainan pasukan itu boleh dibentuk jika tiada syarat dikenakan.
12C5
4C1X2C1X6C1
4C2X2C2X6C1
4C3X2C1X6C1
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A debating team consists of 5 students. These 5 students are chosen from 4 monitors, 2 assistant monitors and 6 prefects.
Calculate the number of different ways the team can be formed if the team contains only monitor and exactly 3 prefects
Satu pasukan bahas terdiri daripada 5 orang pelajar. Pasukan 5 orang pelajar itu dipilih daripada 4 ketua darjah, 2 orang penolong ketua darjah dan 6 orang pengawas.
Hitungkan bilangan cara yang berlainan pasukan itu boleh dibentuk jika pasukan itu mengandungi hanya 1 ketua darjah dan tepat 3 pengawas..
4C1X6C3X1C1
4C1X6C3X2C1
5C1X5C3X5C1
12C1X11C3X8C1
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A coach wants to choose 5 players consisting of 2 boys and 3 girls to form a badminton team. These 5 players are chosen from a group of 4 boys and 5 girls. Find the number of ways the team can be formed.
Seorang jurulatih ingin memilih 5 orang pemain yang terdiri daripada 2 orang pemain lelaki dan 3 orang pemain perempuan untuk membentuk satu pasukan badminton. 5 orang pemain itu dipilih daripada sekumpulan 4 orang lelaki dan 5 orang perempuan. Cari bilangan cara pasukan itu dibentuk.
5C2X3C3
4C2X3C3
4C2X5C3
5C2X4C3
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
There are 6 sweets, each with a different flavour, which are to be divided equally between 2 children.
Find the number of different ways the division of the sweets can be done.
Terdapat 6 biji gula-gula, setiap satu berlainan perisa, yang dibahagikan sama banyak antara 2 orang kanak-kanak.
Cari bilangan cara yang berlainan pembahagian gula-gula itu dapat dilakukan.
6C1X5C1X4C1X3C1X2C1X1C1
6C1X5C1X4C1
6C2X4C2X2C2
6C3X3C3
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
In a box contains of 10 marbles in different colours.
Find the number of way that 3 marbles can be choose from the box.
Dalam sebuah kotak terdapat 10 biji guli yang berlainan warna cari bilangan cara 3 biji guli boleh dipilih dari kotak itu.
10C3
10C1X9C1X8C1
10P1X9P1X8P1
10P3
8.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
In a box contains of 10 marbles in different colours.
Find the number of way that at least 8 marbles can be choose from the box.
Dalam sebuah kotak terdapat 10 biji guli yang berlainan warna cari bilangan cara sekurang-kurangnya 8 biji guli boleh dipilih dari kotak itu.
10C8
10C8 + 10C9
10C8 + 10C9 + 10C10
8C8
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