electrochemistry

electrochemistry

9th Grade

20 Qs

quiz-placeholder

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electrochemistry

electrochemistry

Assessment

Quiz

Chemistry

9th Grade

Hard

Created by

Nurul Hidayah

Used 71+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

A VCE chemistry student sets up a galvanic cell using two standard half-cells with half reactions.

Half-cell 1: Cr3+(aq)+e-→Cr2+(aq)

Half-cell 2: Cr(s)→Cr2+(aq)+2e-

Suitable materials for the electrodes of the two half-cells are

Half-cell 1: Platinum; Half-cell 2: Platinum

Half-cell 1: Platinum; Half-cell 2: Chromium

Half-cell 1: Chromium; Half-cell 2: Chromium

Half-cell 1: Chromium; Half-cell 2: Platinum

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the species strong oxidizing agent?


Cl2(g) + 2e → 2Cl-(aq) Eocell = + 1.36 V

Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V

Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V

Ca2+(aq) + 2e → Ca(s) Eocell = – 2.87 V

Cl2(g)

Cu2+(aq)

Ni2+(aq)

Ca2+(aq)

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which is correct to write cell notation

Anode: Zn

Cathode: Ni

Zn2+ (aq,1M) / Zn (s) // Ni (s) / Ni2+ (aq,1M)

Zn (s) /Zn2+ (aq,1M) // Ni2+ (aq,1M) / Ni (s)

Zn2+ (s,1M) / Zn (aq) // Ni (aq) / Ni2+ (s,1M)

Zn (aq) /Zn2+ (s,1M) // Ni2+ (s,1M) / Ni (aq)

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Calculate standard cell potential for this equation:


Zn2+(aq) + 2e → Zn(s) Eº = – 0.76 V

Cd2+(aq) + 2e → Cd(s) Eº = – 0.40 V

Eocell = -0.36 V

Eocell = -1.16 V

Eocell = +1.16 V

Eocell = +0.36 V

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Based on cell notation below, give the one electrolyte can be used in cathode?


Zn (s) /Zn2+ (aq,1M) // H+ (aq,1M) / H2 (g,1 atm)/graphite (s)

ZnSO4(aq)

H2(aq)

ZnCl2(aq)

HCl(aq)

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Based on the cell notation below, give the suitable X can be used ?


X / H2(g,1 atm)/ H+ (aq,1M) // Ag+ (aq,1M) //Ag (s)

Ag (s)

H (s)

Pt (s)

Zn (s)

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of the pairs give the highest value of voltage cell?


Al3+(aq) + 3e → Al(s) Eocell = - 1.66 V

Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V

Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V

Br2(l) + 2e → 2Br-(aq) Eocell = + 1.07 V

Al and Ni

Cu and Br2

Al and Br2

Cu and Ni

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