Persamaan Lingkaran Ambyar

Persamaan Lingkaran Ambyar

1st Grade

7 Qs

quiz-placeholder

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Persamaan Lingkaran Ambyar

Persamaan Lingkaran Ambyar

Assessment

Quiz

Mathematics

1st Grade

Medium

Created by

Geng Hariyono

Used 7+ times

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Persamaan lingkaran yang berpusat pada (4, 0) dan jari-jari 3 adalah ....

(x+4)2+y2=9(x+4)^2+y^2=9

(x4)2+y2=9(x-4)^2+y^2=9

(x+4)2+y2=3(x+4)^2+y^2=3

x2+(y4)2=9x^2+(y-4)^2=9

x2+(y4)2=3x^2+(y-4)^2=3

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 Titik pusat dan jarijari lingkaranTitik\ pusat\ dan\ jari-jari\ lingkaran   x2+y24x2y20=0x^2+y^2-4x-2y-20=0  adalah ....

 (1,2),r=4(1,2),r=4  

 (1,2),r=5(-1,-2),r=5  

 (2,1),r=5(-2,-1),r=5  

 (2,1),r=5(2,1),r=5  

 (1,2),r=5(1,2),r=5  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 Persamaan lingkaran yang melalui (1,0),(4,3),dan(7,0)adalah....Persamaan\ lingkaran\ yang\ melalui\ (1,0),(4,3),dan(7,0)adalah....  

 x2+y28x4y+7=0x^2+y^2-8x-4y+7=0  

 x2+y28x+16=0x^2+y^2-8x+16=0  

 x2+y28x+7=0x^2+y^2-8x+7=0  

 x2+y2+8x+7=0x^2+y^2+8x+7=0  

 x2+y28x+9=0x^2+y^2-8x+9=0  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 Lingkaran x2+y2+mx6=0 melalui (2,0), nilai m=....Lingkaran\ x^2+y^2+mx-6=0\ melalui\ (2,0),\ nilai\ m=....  

5

4

3

2

1

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 Persamaan lingkaran yang salah satu diameternya menghubungkan titik (-2, -3) dan (4, 1) adalah ....

 x2+y22x+2y11=0x^2+y^2-2x+2y-11=0  

 x2+y22x+2y13=0x^2+y^2-2x+2y-13=0  

 x2+y22x+2y9=0x^2+y^2-2x+2y-9=0  

 x2+y22x+2y4=0x^2+y^2-2x+2y-4=0  

 x2+y22x+2y=0x^2+y^2-2x+2y=0  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Persamaan lingkaran yang berpusat di (0, -2) dan melalui (0, 1) adalah ....

x2+y2+4y9=0x^2+y^2+4y-9=0

x2+y2+2y5=0x^2+y^2+2y-5=0

x2+y2+4y5=0x^2+y^2+4y-5=0

x2+y2+4y4=0x^2+y^2+4y-4=0

x2+y2+2y5=0x^2+y^2+2y-5=0

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Persamaan Lingkaran yang berpusat di (2, 3) dan menyinggung garis 4x + 3y +3 = 0adalah ....

(x+2)2+(y+3)2=16(x+2)^2+(y+3)^2=16

(x2)2+(y3)2=16(x-2)^2+(y-3)^2=16

(x2)2+(y3)2=20(x-2)^2+(y-3)^2=20

(x2)2+(y3)2=4(x-2)^2+(y-3)^2=4

(x3)2+(y2)2=16(x-3)^2+(y-2)^2=16

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