តើមួយណាជារូបមន្តគណនាថាមពលស៊ីនេទិចមធ្យមដែលត្រឹមត្រូវ?

K a v = 3 2 k B T K_{av}=\frac{3}{2}k_BT K a v = 2 3 k B T

K a v = 3 2 n R T K_{av}=\frac{3}{2}nRT K a v = 2 3 n R T

K a v = 3 2 N k B T K_{av}=\frac{3}{2}Nk_BT K a v = 2 3 N k B T

K a v = 3 2 P V K_{av}=\frac{3}{2}PV K a v = 2 3 P V

តើមួយណាជារូបមន្តគណនាថាមពលស៊ីនេទិចសរុបដែលមិនត្រឹមត្រូវ?

K = K a v N K=\frac{K_{av}}{N} K = N K a v

K = 3 2 n R T K=\frac{3}{2}nRT K = 2 3 n R T

K = 3 2 N k B T K=\frac{3}{2}Nk_BT K = 2 3 N k B T

K = 3 2 P V K=\frac{3}{2}PV K = 2 3 P V

ឬសការេនៃការេល្បឿនមធ្យមរបស់ម៉ូលេគុលមានរូបមន្តដូចម្តេចខ្លះ?

V r m s = 3 R T M = 3 k B T m 0 V_{rms}=\sqrt{\frac{3RT}{M}}=\sqrt{\frac{3k_BT}{m_0}} V r m s = M 3 R T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z"> = m 0 3 k B T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z">

V r m s = 3 R T m 0 = 3 k B T m 0 V_{rms}=\sqrt{\frac{3RT}{m_0}}=\sqrt{\frac{3k_BT}{m_0}} V r m s = m 0 3 R T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z"> = m 0 3 k B T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z">

V r m s = 3 R T m 0 = 3 k B T M V_{rms}=\sqrt{\frac{3RT}{m_0}}=\sqrt{\frac{3k_BT}{M}} V r m s = m 0 3 R T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z"> = M 3 k B T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z">

V r m s = 3 R T M = 3 k B T M V_{rms}=\sqrt{\frac{3RT}{M}}=\sqrt{\frac{3k_BT}{M}} V r m s = M 3 R T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z"> = M 3 k B T <path d="M424,2478c-1.3,-0.7,-38.5,-172,-111.5,-514c-73, -342,-109.8,-513.3,-110.5,-514c0,-2,-10.7,14.3,-32,49c-4.7,7.3,-9.8,15.7,-15.5, 25c-5.7,9.3,-9.8,16,-12.5,20s-5,7,-5,7c-4,-3.3,-8.3,-7.7,-13,-13s-13,-13,-13, -13s76,-122,76,-122s77,-121,77,-121s209,968,209,968c0,-2,84.7,-361.7,254,-1079 c169.3,-717.3,254.7,-1077.7,256,-1081c4,-6.7,10,-10,18,-10H400000v40H1014.6 s-87.3,378.7,-272.6,1166c-185.3,787.3,-279.3,1182.3,-282,1185c-2,6,-10,9,-24,9 c-8,0,-12,-0.7,-12,-2z M1001 80H400000v40H1014z">

បណ្តារូបមន្តខាងក្រោម តើមួយណាដែលជារូបមន្តថាមពលស៊ីនេទិចសរុបត្រឹមត្រូវទាំងអស់?

K = N K a v = 3 2 n R T = 3 2 N k B T = 3 2 P V K=NK_{av}=\frac{3}{2}nRT=\frac{3}{2}Nk_BT=\frac{3}{2}PV K = N K a v = 2 3 n R T = 2 3 N k B T = 2 3 P V

K = n K a v = 3 2 n R T = 3 2 N k B T = 3 2 P V K=nK_{av}=\frac{3}{2}nRT=\frac{3}{2}Nk_BT=\frac{3}{2}PV K = n K a v = 2 3 n R T = 2 3 N k B T = 2 3 P V

K = N K a v = 3 2 n R T = 3 2 k B T = 3 2 P V K=NK_{av}=\frac{3}{2}nRT=\frac{3}{2}k_BT=\frac{3}{2}PV K = N K a v = 2 3 n R T = 2 3 k B T = 2 3 P V

K = N K a v = 3 2 n R T = 3 2 N k B T = 3 P V 2 N K=NK_{av}=\frac{3}{2}nRT=\frac{3}{2}Nk_BT=\frac{3PV}{2N} K = N K a v = 2 3 n R T = 2 3 N k B T = 2 N 3 P V

ក្នុងបណ្តារូបមន្តខាងក្រោម តើមួយណាជារូបមន្តគណនាថាមពលស៊ីនេទិចមធ្យមត្រឹមត្រូវទាំងអស់?

K a v = 3 2 P V N = 3 2 k B T K_{av}=\frac{3}{2}\ \frac{PV}{N}=\frac{3}{2}k_BT K a v = 2 3 N P V = 2 3 k B T

K a v = 3 2 P V = 3 2 k B T K_{av}=\frac{3}{2}PV=\frac{3}{2}k_BT K a v = 2 3 P V = 2 3 k B T

K a v = 2 3 P V N = 3 2 k B T K_{av}=\frac{2}{3}\frac{PV}{N}=\frac{3}{2}k_BT K a v = 3 2 N P V = 2 3 k B T

K a v = 3 2 P V N = 3 2 N k B T K_{av}=\frac{3}{2}\ \frac{PV}{N}=\frac{3}{2}Nk_BT K a v = 2 3 N P V = 2 3 N k B T

ម៉ូលេគុលឧស្ម័នអ៊ីដ្រូសែនមានសីតុណ្ហភាព 27 ° C 27\ \degree C 2 7 ° C ។ តើថាមពលស៊ីនេទិចមធ្យមមានតម្លៃស្មើប៉ុន្មាន? បើ k B = 1.38 × 1 0 − 23 J . K − 1 k_B=1.38×10^{-23}J.K^{-1} k B = 1 . 3 8 × 1 0 − 2 3 J . K − 1

621 × 1 0 − 23 J 621×10^{-23}J 6 2 1 × 1 0 − 2 3 J

37.26 × 1 0 − 23 J 37.26×10^{-23}J 3 7 . 2 6 × 1 0 − 2 3 J

414 × 1 0 − 23 J 414×10^{-23}J 4 1 4 × 1 0 − 2 3 J

62.1 × 1 0 − 23 J 62.1×10^{-23}J 6 2 . 1 × 1 0 − 2 3 J

ថេរសកលនៃឧស្ម័នមានតម្លៃប៉ុន្មាន?

R = 8.31 J . m o l − 1 K − 1 R=8.31\ J.mol^{-1}K^{-1} R = 8 . 3 1 J . m o l − 1 K − 1

R = 1.38 J . m o l − 1 K − 1 R=1.38J.mol^{-1}K^{-1} R = 1 . 3 8 J . m o l − 1 K − 1

R = 831 J . m o l − 1 K − 1 R=831\ J.mol^{-1}K^{-1} R = 8 3 1 J . m o l − 1 K − 1

R = 1.38 × 1 0 − 23 J . m o l − 1 K − 1 R=1.38\ ×10^{-23\ }J.mol^{-1}K^{-1} R = 1 . 3 8 × 1 0 − 2 3 J . m o l − 1 K − 1

ថេរបុលស្មាន់មានតម្លៃប៉ុន្មាន?

1.38 × 1 0 − 23 J . K − 1 1.38×10^{-23}\ J.K^{-1} 1 . 3 8 × 1 0 − 2 3 J . K − 1

8.31 × 1 0 − 23 J . K − 1 8.31×10^{-23}\ J.K^{-1} 8 . 3 1 × 1 0 − 2 3 J . K − 1

8.31 J . m o l − 1 K − 1 8.31\ J.mol^{-1}K^{-1} 8 . 3 1 J . m o l − 1 K − 1

1.38 × 1 0 23 J . K − 1 1.38×10^{23}J.K^{-1} 1 . 3 8 × 1 0 2 3 J . K − 1

តើរូបមន្តខាងក្រោម មួយណាដែលជារូបមន្តថេរសកលនៃឧស្ម័នដែលត្រឹមត្រូវ?

R = N A × k B R=N_A×k_B R = N A × k B

R = N A k B R=\frac{N_A}{k_B} R = k B N A

R = k B N A R=\frac{k_B}{N_A} R = N A k B

R = N × k B R=N×k_B R = N × k B

តើរូបមន្តមួយណា ដែលមិនត្រឹមត្រូវ?

K a v = 2 3 k B T K_{av}=\frac{2}{3}k_BT K a v = 3 2 k B T

P = 2 K a v N 3 V P=\frac{2K_{av}N}{3V} P = 3 V 2 K a v N

P = 2 K 3 V P=\frac{2K}{3V} P = 3 V 2 K

ទ្រឹស្តីស៊ីនេទិចនៃឧស្ម័ន ថ្នាក់ទី 12

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Quiz

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Physics

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12th Grade

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Practice Problem

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Medium

Sopheak Oum

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22 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

ឃ្លាណាមួយជាទ្រឹស្តីស៊ីនេទិចនៃឧស្ម័នដែលមិនត្រឹមត្រូវ?

ម៉ូលេគុលមានចលនាឥតឈប់ឈរ និងគ្មានសណ្តាប់ធ្នាប់

ទង្គិចរវាងម៉ូលេគុលនិងផ្ទៃធុងជាទង្គិចខ្ទាត់

ចន្លោះពេលទង្គិច ម៉ូលេគុលមានល្បឿនប្រែប្រួល

ថាមពលស៊ីនេទិចមធ្យមនៃម៉ូលេគុលនីមួយៗអាស្រ័យនឹងសីតុណ្ហភាព

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

សមីការភាពនៃឧស្ម័នបរិសុទ្ធដែលត្រឹមត្រូវគឺ៖

$PV=NRT$

$PV=nk_BT$

$PV=Nk_BT$

$PV=N_Ak_BT$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

ក្នុងចំណោមសមីការភាពនៃឧស្ម័នបរិសុទ្ធខាងក្រោម តើមួយណាដែលមិនត្រឹមត្រូវ?

$PV=nRT$

$PV=\frac{M}{m}RT$

$PV=\frac{N}{N_A}RT$

$PV=nN_Ak_BT$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

រូបមន្តចំនួនម៉ូល ដែលត្រឹមត្រូវគឺ.....

$n=m×M$

$n=\frac{m_0}{M}$

$n=\frac{N}{N_A}$

$n=\frac{m}{m_0}$

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

រូបមន្តចំនួនម៉ូលដែលមិនត្រឹមត្រូវគឺ.....

$n=\frac{N}{N_A}$

$n=\frac{m}{M}$

$n=\frac{m_0}{M}$

$n=\frac{PV}{RT}$

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

ម៉ាសម៉ូលនៃឧស្ម័នតាងដោយ.....

$M$

$n$

$m$

$m_0$

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

ម៉ាសឧស្ម័នតាងដោយ......

$M$

$m$

$m_0$

$N$

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

ម៉ាសម៉ូលេគុលនៃឧស្ម័នតាងដោយ.....

$M$

$m$

$m_0$

$n$

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

ក្នុងការគណនា សម្ពាធត្រូវបានគិតខ្នាតជាអ្វី?

$Pa$

$atm$

$mmHg$

$Bar$

10.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

តើខ្នាតណាមួយខាងក្រោម មិនមែនជាខ្នាតរបស់សម្ពាធ?

$N.m^{-2}$

$atm$

$Pa$

$Nm$

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10th - 12th Grade

ទ្រឹស្តីស៊ីនេទិចនៃឧស្ម័ន ថ្នាក់ទី 12

22 questions

ឃ្លាណាមួយជាទ្រឹស្តីស៊ីនេទិចនៃឧស្ម័នដែលមិនត្រឹមត្រូវ?

សមីការភាពនៃឧស្ម័នបរិសុទ្ធដែលត្រឹមត្រូវគឺ៖

ក្នុងចំណោមសមីការភាពនៃឧស្ម័នបរិសុទ្ធខាងក្រោម តើមួយណាដែលមិនត្រឹមត្រូវ?

រូបមន្តចំនួនម៉ូល ដែលត្រឹមត្រូវគឺ.....

រូបមន្ត​ចំនួនម៉ូលដែលមិនត្រឹមត្រូវគឺ.....

ម៉ាសម៉ូលនៃឧស្ម័នតាងដោយ.....

ម៉ាសឧស្ម័នតាងដោយ......

ម៉ាសម៉ូលេគុលនៃឧស្ម័នតាងដោយ.....

ក្នុងការគណនា សម្ពាធត្រូវបានគិតខ្នាតជាអ្វី?

តើខ្នាតណាមួយខាងក្រោម មិនមែនជាខ្នាតរបស់សម្ពាធ?

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រូបមន្តចំនួនម៉ូលដែលមិនត្រឹមត្រូវគឺ.....