trigonometria

trigonometria

9th Grade

13 Qs

quiz-placeholder

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trigonometria

trigonometria

Assessment

Quiz

Mathematics

9th Grade

Hard

CCSS
HSG.SRT.C.8, HSG.SRT.C.6, 3.MD.D.8

+2

Standards-aligned

Created by

Ana Almeida

Used 752+ times

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13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A razão cosseno corresponde:

cateto adjacente/hipotenusa

cateto oposto/hipotenusa

cateto oposto/cateto adjacente

cosseno/seno

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A razão tangente é calculada por:

cateto oposto/cateto adjacente

cateto oposto/cateto oposto

hipotenusa/cateto adjacente

hipotenusa/cateto oposto

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Atendendo ao triângulo retângulo representado na figura, podemos afirmar que:

sinρ1,3\sin\rho\approx1,3

cosρ=0,8\cos\rho=0,8

sinρ=0,6\sin\rho=0,6

tanρ1,3\tan\rho\approx1,3

Tags

CCSS.HSG.SRT.C.6

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Na figura, está representado um triângulo retângulo.
Apresentam-se a seguir quatro igualdades. Apenas uma está correta. Qual?

sinx=bc\sin x=\frac{b}{c}

sinx=ba\sin x=\frac{b}{a}

sinx=ca\sin x=\frac{c}{a}

sinx=ab\sin x=\frac{a}{b}

Tags

CCSS.HSG.SRT.C.6

5.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Media Image

Qual ou quais as expressões que permitem calcular o valor de α?\alpha?  

tan1(34)\tan^{-1}\left(\frac{3}{4}\right)

tan1(43)\tan^{-1}\left(\frac{4}{3}\right)

cos1(35)\cos^{-1}\left(\frac{3}{5}\right)

sin1(45)\sin^{-1}\left(\frac{4}{5}\right)

cos1(45)\cos^{-1}\left(\frac{4}{5}\right)

Tags

CCSS.HSG.SRT.C.8

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Atendendo aos dados da figura, qual é aproximadamente a altura do penhasco?

98 metros.

69 metros.

120 metros.

Não é possível determinar a altura aproximada do penhasco.

Tags

CCSS.HSG.SRT.C.8

7.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Media Image

Considera a figura e indica qual( ais) a(as) afirmação(ões)  falsa(s).

A amplitude do ângulo  CABCAB  é  60º60º .

A equação  tan(60º)=AC60\tan\left(60º\right)=\frac{\overline{AC}}{60}  permite calcular a distância entre a praia e o castelo.

A  distância entre a praia e o castelo é de, aproximadamente 100 m.                                                 

 AB=120 m\overline{AB}=120\ m  

Tags

CCSS.HSG.SRT.C.8

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