Conditional Probabilities

Conditional Probabilities

10th - 12th Grade

25 Qs

quiz-placeholder

Similar activities

PERSAMAAN EKSPONEN

PERSAMAAN EKSPONEN

10th Grade

20 Qs

Solving Absolute Value Equations

Solving Absolute Value Equations

11th - 12th Grade

20 Qs

Sistem Persamaan Linear Dua Variabel

Sistem Persamaan Linear Dua Variabel

10th Grade

20 Qs

Factorisation and algebraic fractions

Factorisation and algebraic fractions

9th - 11th Grade

20 Qs

ALGEBRAIC FORMULAE

ALGEBRAIC FORMULAE

7th - 11th Grade

20 Qs

BILANGAN BERPANGKAT, BENTUK AKAR DAN LOGARITMA

BILANGAN BERPANGKAT, BENTUK AKAR DAN LOGARITMA

10th Grade

20 Qs

Bab 2 : Pemfaktoran dan Pecahan Algebra (Tingkatan 2)

Bab 2 : Pemfaktoran dan Pecahan Algebra (Tingkatan 2)

1st - 10th Grade

20 Qs

MATEMATIKA VEKTOR KELAS X

MATEMATIKA VEKTOR KELAS X

10th Grade

21 Qs

Conditional Probabilities

Conditional Probabilities

Assessment

Quiz

Mathematics

10th - 12th Grade

Medium

CCSS
HSS.CP.B.7, HSS.CP.B.6, HSS.CP.A.4

+3

Standards-aligned

Created by

Christopher Schorsten

Used 21+ times

FREE Resource

25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability of randomly selecting a student who received a sweater as a gift?

P(Sweater)=2376P\left(Sweater\right)=\frac{23}{76}

P(Sweater)=4676P\left(Sweater\right)=\frac{46}{76}

P(Sweater)=523P\left(Sweater\right)=\frac{5}{23}

P(Sweater)=546P\left(Sweater\right)=\frac{5}{46}

Tags

CCSS.8.SP.A.4

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability of randomly selecting a student who received a socks as a gift and was surprised?

P(Socks Surprised)=5676P\left(Socks\ \cup Surprised\right)=\frac{56}{76}

P(Socks Surprised)=4276P\left(Socks\ \cap Surprised\right)=\frac{42}{76}

P(Socks Surprised)=3276P\left(Socks\ \cap Surprised\right)=\frac{32}{76}

P(Socks Surprised)=8876P\left(Socks\ \cup Surprised\right)=\frac{88}{76}

Tags

CCSS.HSS.CP.B.7

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability that a randomly selected student received underwear as a gift or was not surprised?

P(UnderwearSurprisedC)=276P\left(Underwear\cap Surprised^C\right)=\frac{2}{76}

P(UnderwearSurprisedC)=211P\left(Underwear\cup Surprised^C\right)=\frac{2}{11}

P(UnderwearSurprisedC)=3976P\left(Underwear\cup Surprised^C\right)=\frac{39}{76}

P(UnderwearSurprisedC)=946P\left(Underwear\cup Surprised^C\right)=\frac{9}{46}

Tags

CCSS.HSS.CP.B.7

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Given a student was surprised with the gift, what is the probability that he or she got socks?

P(SurprisedSocks)=3242P\left(Surprised\left|Socks\right|\right)=\frac{32}{42}

P(SocksSurprised)=3246P\left(Socks\left|Surprised\right|\right)=\frac{32}{46}

P(SurprisedSocks)=3276P\left(Surprised\left|Socks\right|\right)=\frac{32}{76}

P(SurprisedSocks)=819P\left(Surprised\left|Socks\right|\right)=\frac{8}{19}

Tags

CCSS.HSS.CP.A.4

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability that saw Frozen 2?

P(Frozen 2)=32116P\left(Frozen\ 2\right)=\frac{32}{116}

P(Frozen 2)=32238P\left(Frozen\ 2\right)=\frac{32}{238}

P(Frozen 2)=3257P\left(Frozen\ 2\right)=\frac{32}{57}

P(Frozen 2)=57238P\left(Frozen\ 2\right)=\frac{57}{238}

Tags

CCSS.8.SP.A.4

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability of randomly selecting a student who saw Star Wars and an Evening Show?

P(Star WarsEvening Show)=85238P\left(Star\ Wars\cap Evening\ Show\right)=\frac{85}{238}

P(Star WarsEvening Show)=122238P\left(Star\ Wars\cap Evening\ Show\right)=\frac{122}{238}

P(Star WarsEvening Show)=211238P\left(Star\ Wars\cup Evening\ Show\right)=\frac{211}{238}

P(Star WarsEvening Show)=85145P\left(Star\ Wars\cup Evening\ Show\right)=\frac{85}{145}

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the probability of randomly selecting a student who saw Jumanji or a Matinee?

P(JumanjiMatinee)=24238P\left(Jumanji\cup Matinee\right)=\frac{24}{238}

P(JumanjiMatinee)=12238P\left(Jumanji\cap Matinee\right)=\frac{12}{238}

P(JumanjiMatinee)=24116P\left(Jumanji\cap Matinee\right)=\frac{24}{116}

P(JumanjiMatinee)=128238P\left(Jumanji\cup Matinee\right)=\frac{128}{238}

Tags

CCSS.HSS.CP.B.7

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?