CBA 3 Review 2019/2020

 $24-5^2$  

• -1

• 14

• 1

• -14

 $4\left(3+5\right)-3\times9^2$  

• 14 x 81

•  $17-27^2$  

• 12 + 20 - 54

• 4(8) - 3 x 81

Which expression is equivalent to  $\left(6\cdot p\right)+3$  

•  $3-\left(6\cdot p\right)$  

•  $3+\left(p\cdot6\right)$  

•  $6+3\cdot p$  

•  $6\cdot\left(3+p\right)$  

Bob writes the expression  $y+9\cdot\frac{3}{4}$  . Which expressio is equilvent to the one Bob wrote?

•  $\left(9\cdot3\div4\right)+y$  

•  $9+y\cdot\left(3\div4\right)$  

•  $\left(y+9\right)\left(3\div4\right)$  

•  $None\ of\ these$  

After 4 new students joined a class, the class had 32 students. Which equation can be used to find n, the number of students in the class before the 4 new students joined?

• $\frac{n}{4}=32$

• $n-4=32$

• $4n=32$

• $n+4=32$

Which situation could be represented by the equation

10.75 = 5.5n?

• Paul ran 5.5 miles.

  He ran each mile in 10.75 minutes.

  What is n, the total number of minutes it took Paul to run 5.5 miles?

• Paul ran a total of 10.75 on Monday.

  He ran 5.5 miles in the morning and the rest of the miles in the evening.

  What is n, the number of miles Paul ran in the evening?

• Paul ran a total of 10.75.

  He ran 5.5 miles each hour.

  What is n, the number of hours Paul ran?

• Paul ran 10.75 hours one week and 5.5 hours the next week. What is n, the total number of hours Paul ran during these weeks?

Ms. Gallegos burns 236 calories riding her bike each hour. She wants to burn more than 590 calories riding her bike at the same rate.
Which inequality represnts all possible values for t, the number of hours Ms. Gallegos must ride her bike to burn more than 590 calories?

• $t>2.5$

• $t<2.5$

• $t>0.4$

• $t<0.4$

The area of a rectangle is 45.5 square inches. The base of the rectangle is 7 inches. What is the height of the rectangle in inches?

• 315.5 in

• 6.5 in

• 15..75 in

• 38.5 in

Which inequality is true if p = 3.4?

• $3p<10.2$

• $13.6\le3.9p$

• $5p>17.1$

• $8.5\ge2.5p$

 $Which\ equation\ has\ a\ solution\ of\ \frac{3}{4}for\ n?$  

•  $n-1=\frac{2}{4}$  

•  $12n=16$  

•  $20n=15$  

•  $1\ \frac{2}{4}+n=4$