Point slope and standard form - kaplan

Which of these represents the standard form of a linear equation?

• y - y₁ = m(x - x₁)
• Ax + By = C
• y = mx + b

Tags

CCSS.HSA.CED.A.2

Find the x and y intercepts
5x - 3y = 15

• x intercept is 3 
  y intercept is 5
• x intercept is -3
  y intercept is 5
• x intercept is 5
  y intercept is -3
• x intercept is 3
  y intercept is -5

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

Change the following equation to slope-intercept form:
5x - 5y = 25

• y = x - 5
• y = 5x - 1
• y = -x + 5
• y = 5x + 1

Tags

CCSS.HSA.SSE.B.3

Which of these represents the point-slope form of a linear equation?

• y - y₁ = m(x - x₁)
• Ax + By = C
• y = mx + b

Tags

CCSS.HSG.GPE.B.5

Write the equation in point-slope form of the line that passes through the given point and has the given slope.
(4, -7); m = -1/4

• y + 7 = -1/4(x - 4)
• y - 4 = -1/4(x + 7)
• y + 7 = 4(x - 4)
• y - 7 = -1/4(x - 4)

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.B.5

For the equation
y - 3 = 2(x + 4),
the line has a slope of 2 and contains what point?

• (-4, 3)
• (3, -4)
• (-3, -4)
• (-4, -3)

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

For the equation
y + 1 = -3(x - 5),
the line contains the point (5, -1) and has a slope of?

• -1
• 1
• -3
• 5

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSG.GPE.B.5

CCSS.HSS.ID.C.7

convert to slope intercept form:

y - 3 = 3(x - 1)

• y = 3x + 6

• y = 3x - 6

• y = 3x

• y=3x - 4

Tags

CCSS.HSA.REI.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Convert to slope intercept form

• y=x+2

• y=3x+6

• y=-x+2

• y=-3x-2

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSS.ID.C.7

what is the first step to solve for slope intercept form on

-x + 4y = 11

• subtract 11 from both sides

• add x to both sides

• subtract x from both sides

• put in th y=

Tags

CCSS.HSA.CED.A.4

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3