NC Math 3 EOC Review

NC Math 3 EOC Review

10th - 12th Grade

15 Qs

quiz-placeholder

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NC Math 3 EOC Review

NC Math 3 EOC Review

Assessment

Quiz

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
HSA.APR.D.6, HSF.BF.B.5, HSA.APR.B.2

+16

Standards-aligned

Created by

Karen Desilva

Used 381+ times

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What is the value of the expression  f(4)+18(f(1))f(8)f\left(-4\right)+18\left(f\left(1\right)\right)-f\left(8\right)  

9

-39

-31

-9

Tags

CCSS.HSF.IF.A.2

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 Solve:   4x+1+3x=1Solve:\ \ \ \frac{-4}{x+1}+\frac{3}{x}=1  

 3-3  

 {3,1}\left\{-3,1\right\}  

 {1,3}\left\{-1,3\right\}  

 11  

Tags

CCSS.HSA.REI.A.2

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which function has a point of discontinuity at  x=4x=4  when graphed?

 f(x)=x4+2f\left(x\right)=\left|x-4\right|+2  

 f(x)=x4x2f\left(x\right)=\frac{x-4}{x^2}  

Media Image

 f(x)=x+2x216f\left(x\right)=\frac{x+2}{x^2-16}  

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The function  y=a(1.40)ty=a\left(1.40\right)^t  models the value of an investment after  tt  years.  Based on the function, what is the approximate monthly interest rate?

 2.8%2.8\%  

 11.6%11.6\%  

 3.3%3.3\%  

 5.7%5.7\%  

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.4

CCSS.HSF.LE.B.5

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the remainder when x3+1x^3+1  is divided by  x+3x+3 

 2828  

 00  

 2-2  

 26-26  

Tags

CCSS.HSA.APR.B.2

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

The graph of the function  p(x)=x3x213x3p\left(x\right)=x^3-x^2-13x-3  has a zero at  3-3  .  What are the other zeros of the function?

 2-2  and  22  

 2±52\pm\sqrt{5}  

 1±7-1\pm\sqrt{7}  

 4-4  and  11  

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 Write a polynomial  p(x)p\left(x\right)  that has zeros of 1(multiplicity 2),  4-4  (multiplicity 1) and  22  (multiplicity 1).

 p(x)=x411x2+18x8p\left(x\right)=x^4-11x^2+18x-8  

 p(x)=x3+x210x+8p\left(x\right)=x^3+x^2-10x+8  

 p(x)=x4+2x39x2+2x+8p\left(x\right)=x^4+2x^3-9x^2+2x+8  

 p(x)=x37x210x8p\left(x\right)=x^3-7x^2-10x-8  

Tags

CCSS.HSA.APR.B.3

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