Molar Mass & Mole Conversions Warm Up Review

Molar Mass & Mole Conversions Warm Up Review

10th - 12th Grade

8 Qs

quiz-placeholder

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Molar Mass & Mole Conversions Warm Up Review

Molar Mass & Mole Conversions Warm Up Review

Assessment

Quiz

Chemistry

10th - 12th Grade

Medium

Created by

Pamela Slater

Used 12+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The mass of a molecule is found by

adding the masses of all the atoms in the molecule.

dividing the total mass of all the atoms in the molecule by 6.022 x 1023.

multiplying the total mass of all the atoms in the molecule by 6.022 x 1023.

dividing the total mass of all the atoms in the molecule by the total number of atoms.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For any molecule, formula unit, or ion, the sum of the average atomic masses of all the atoms represented in a formula is the

formula mass.

ionic mass

molecular mass

atomic mass

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct formula mass for zinc hydroxide, Zn(OH)2?

83.41 g

99.41 g

83.41 amu

82.38 g

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

One mole of potassium atoms has a mass of

1 g

39.10 g

78.20 g

6.022 x 1023 g.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A compound's molar mass is numerically equal to

the total number of atoms in the molecule.

the total number of moles of the compound.

its mass number.

its formula mass.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many total moles of atoms are there in one mole of silver(I) phosphate, Ag3PO4?

3

7

8

11

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct molar mass of Ag3PO4?

418.58 g/mol

387.61 g/mol

154.84 g/mol

52.32 g/mol

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which statement shows how to correctly convert from the mass of a compound in grams to the amount of that compound in moles?

 molar mass (g)1 mol×1mass (g)\frac{molar\ mass\ \left(g\right)}{1\ mol}\times\frac{1}{mass\ \left(g\right)}  

 (molarmass(g)molx 6.022x1023\frac{\left(molarmass(g\right)}{mol}x\ 6.022x10^{23}  

 mass (g) x molarmass(g)1 molemass\ \left(g\right)\ x\ \frac{molarmass\left(g\right)}{1\ mole}  

 mass (g) x 1 molemolar mass (g)mass\ \left(g\right)\ x\ \frac{1\ mole}{molar\ mass\ \left(g\right)}