Alg 2 Module 2 Review

|v + 8| − 5 = 2

• {-1,-15}

• {-1,15}

• {-15,1}

• No Solution

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.A.2

CCSS.HSA.REI.B.3

|−2n| + 10 = −50

• {30, -30}

• 30

• -30

• No Solution

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Solve:

3 | 2x + 7| - 7 < -4

• x > -3 and x < -4

• x < -3 and x > -4

• x < -3 and x < -4

• no solution

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

What is the first step? 

• Get absolute value alone by subtracting 5 from both sides
• Get absolute value alone by dividing by 5 on both sides
• Split into two equations

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

The street built in the city must be 25 feet in width with a tolerance of 0.5 feet. Streets that are not within the tolerated widths must be repaired. Which of the following inequalities can be used to assess which streets are within tolerance? (W is the width of the street) .

• |W - 25| ≤ .5
• |W - .5| ≤ 25
• |W - 25| ≥ .5
• |W - .5| ≥ 25

Tags

CCSS.7.EE.B.3

A company sells 20-ounce bottles of sports drink. The actual volume of liquid in the bottle must be within 0.03 ounces. Which volume would NOT be included in the range of liquid?

• 19.93
• 20.013
• 20.02
• 19.99

Tags

CCSS.5.NBT.A.4

What is the equation of the absolute value function?

• f(x)= 4|x+3|

• f(x)= 4|x| + 3

• f(x)= 4|x| - 3

• f(x)= 4|x - 3|

Tags

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7