Algebra 2 Unit 8 Quiz 1 Review

Algebra 2 Unit 8 Quiz 1 Review

9th - 12th Grade

14 Qs

quiz-placeholder

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Algebra 2 Unit 8 Quiz 1 Review

Algebra 2 Unit 8 Quiz 1 Review

Assessment

Quiz

Mathematics

9th - 12th Grade

Medium

CCSS
HSF.LE.A.1, HSA.CED.A.1, HSF.BF.B.5

+10

Standards-aligned

Created by

Shannon Day

Used 4+ times

FREE Resource

14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the horizontal asymptote for the graph of 
f(x)=-2(3)x+4-8 ?
y=8
y=-8
x=-8
x=-4

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the range for the graph of

f(x)=-2(3)x+4-8 ?

y>-8

y<-8

y>4

y<-4

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the domain and range of the function y=2x ?

Use the graph to help!

Domain: All Real Numbers

Range: y>0

Domain: All Real Numbers

Range: y>1

Domain: −2<x<∞

Range: y>0

Domain: All Real Numbers

Range: y<0

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the horizontal asymptote and what transformations have taken place?
y = 2x+2 + 1
y = 2
right 2, up 1
y = 1
left 2, up 1
y = 1
right 2, up 1
y = 2
right 1, up 2

Tags

CCSS.HSF.BF.B.3

CCSS.HSF.IF.C.7

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image
Which equation best describes the graph? 
y = 2x + 4
y = 2x - 3
y = 2x - 4
y = 2x + 3 

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

CCSS.HSF.LE.A.1

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write an exponential function to model the situation. Solve.
2) The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year. What will the cost be after 4 years?
C(t) = 12000(1.06)t ; $3149.72
C(t) = 12000(.06)t ; $3149.72
C(t) = 12000(.06)t ; $1472.95
C(t) = 12000(1.06)t ; $15149.72

Tags

CCSS.HSF.LE.A.2

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Write an exponential function to model the situation. Solve.
6) The value of a car is $18000 and is depreciating at a rate of 12% per year. What will the value of the car be after 10 years?
V(t) = 18000(.88)t ; $12986.98
V(t) = 18000(.12)t ; $12986.98
V(t) = 18000(.88)t ; $5013.02
V(t) = 18000(.12)t ; $5013.02

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